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vodomira [7]
3 years ago
13

Hellllppp!!!! Please!Match the numbers with the correct label.

Mathematics
1 answer:
rusak2 [61]3 years ago
7 0

Answer:

(a = 1/7 (b = .2 (c = 3/9

Step-by-step explanation:

1/7 = .14

1/4 = .25

3/9 = .33

a & b are lower than 1/4 and c is higher

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Jenny picked 25 roses. she gave away 10 roses. What percent of the roses did Jenny give away?
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Divide 10 by 25, which would get you 4. Move the decimal over two to the left, because you wanted a percentage.

Jenny gave away 40% of the roses.
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10 Y plus 9Y minus 6Y plus 6Y simplified
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10 y plus 9 y minus 6 y plus 6 y

=> 10y + 9y - 6y + 6y
= 10y + 9y - 0 = 19y

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Find the volume of this cylinder. <br><br><br> As soon as possible please..
Alexxandr [17]

Answer:

144

Step-by-step explanation:

V=PIr^2h

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Read 2 more answers
Suppose there are 297 students going on a field trip. If each school bus can carry 58 students, estimate the number of buses tha
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5 0
3 years ago
One tire manufacturer claims that his tires last an average of 42,000 miles with a standard deviation of 7800 miles. A random sa
snow_lady [41]

Answer:

89.97% probability that the average of these 100 tires will last greater than 41,000 miles.

Step-by-step explanation:

The solve this problem, it is important to know the Normal Probability distribution and the Central Limit Theorem.

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, a large sample size can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

\mu = 42000, \sigma = 7800, n = 100, s = \frac{7800}{\sqrt{100}} = 780

What is the probability that the average of these 100 tires will last greater than 41,000 miles?

This is 1 subtracted by the pvalue of Z when X = 41000.

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem, we use s instead of \sigma.

Z = \frac{X - \mu}{s}

Z = \frac{41000 - 42000}{780}

Z = -1.28

Z = -1.28 has a pvalue of 0.1003.

So there is a 1-0.1003 = 0.8997 = 89.97% probability that the average of these 100 tires will last greater than 41,000 miles.

6 0
3 years ago
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