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2 years ago

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Three years ago, Ava lent her sister $400 to buy some clothes. Today Ava’s sister paid her loan in full with $454. What simple a

nnual interest rate did she pay?

2 answers:

Ostrovityanka [42]2 years ago

5 0

Ava's sister paid a 4.5% annual interest rate

Her sister paid $54 more than she borrowed, divide that by 3 (years till she paid)

54/3 = 18

That's $18 for every year she'd had the $400 loan out, divide it by 4 to get the percentage

18/4 = 4.5/100 = 4.5%

forsale [732]2 years ago

3 0

Answer:

the answer would be 4.5%

Step-by-step explanation:

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(CO 4) In a sample of 8 high school students, they spent an average of 24.8 hours each week doing sports with a sample standard

AveGali [126]

Answer:

(22.12, 27.48)

Step-by-step explanation:

Given : Significance level : $\alpha: 1-0.95=0.05$

Sample size : n= 8 , which is a small sample (n<30), so we use t-test.

Critical values using t-distribution: $t_{n-1,\alpha/2}=t_{7,0.025}=2.365$

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Standard deviation : $\sigma=3.2\text{ hours}$

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$\overline{x}\pm t_{n-1,\alpha/2}\dfrac{\sigma}{\sqrt{n}}$

i.e. $24.8\pm(2.365)\dfrac{3.2}{\sqrt{8}}$

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2 years ago

A basic cellular phone plan costs $4 per month for 70 calling minutes. Additional time costs $0.10 per minute. The formula C= 4+

Harrizon [31]

Answer:

For a monthly cost of at least $7 and at most $8, you can have between 100 and 110 calling minutes.

Step-by-step explanation:

The problem states that the monthly cost of a celular plan is modeled by the following function:

$C(x) = 4 + 0.10(x-70)$

In which C(x) is the monthly cost and x is the number of calling minutes.

How many calling minutes are needed for a monthly cost of at least $7?

This can be solved by the following inequality:

$C(x) \geq 7$

$4 + 0.10(x - 70) \geq 7$

$4 + 0.10x - 7 \geq 7$

$0.10x \geq 10$

$x \geq \frac{10}{0.1}$

$x \geq 100$

For a monthly cost of at least $7, you need to have at least 100 calling minutes.

How many calling minutes are needed for a monthly cost of at most 8:

$C(x) \leq 8$

$4 + 0.10(x - 70) \leq 8$

$4 + 0.10x - 7 \leq 8$

$0.10x \leq 11$

$x \leq \frac{11}{0.1}$

$x \leq 110$

For a monthly cost of at most $8, you need to have at most 110 calling minutes.

For a monthly cost of at least $7 and at most $8, you can have between 100 and 110 calling minutes.

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3 years ago

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stiks02 [169]

Answer:

Take a look at my notes. I hope this helps.

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