Answer:
c. (x + 3)
Step-by-step explanation:
using factor theorem
if x - 3 is a factor then p(a) = 0
p(a)= x^3 - 3x^2 - 4x + 12
a.(x-3)
p(3) = (3)^3 - 3(3)^2 - 4(3) + 12
= 27 - 27 - 12 + 12
= 0
therefore x-3 is a factor
b.(x + 2)
p(-2) = (-2)^3 - 3(-2)^2 - 4(-2) + 12
= -8 -12 + 8 + 12
,= 0
therefore x + 2 is a factor
c.(x + 3)
p(-3) = (-3)^3 - 3(-3)^2 - 4(-3) + 12
= -27 -27 + 12 + 12
= -30
therefore x + 3 is not a factor
d.(x-2)
p(2) = (2)^3 - 3(2)^2 - 4(2) + 12
= 8 -12 - 8 + 12
= 0
therefore x - 2 is a factor
2.4 ÷ 8= 0.3
The decimal stays the same.
Hoped this helped.
~Bob Ross®
Step-by-step explanation:
- (3,3)
- (2,1)
- (1,3)
- (0,3)
Or the other way around
(0,3)
(1,3)
(2,1)
(3,3)
by the way this is a function because all the outputs have one input. Nothing is being shared.
False one pound is equal to less than one kilo
Answer:
4+2=6 4-2=6
Step-by-step explanation:
Y=2 6-2=4 4+2=6 4-2=2
