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3 years ago

What’s the value of X in this triangle

Mathematics

2 answers:

bearhunter [10]3 years ago

6 0

Answer:

x = 85

Step-by-step explanation:

Step 1: Solve x

∠x = 180 - 27 - 68

∠x = 85

Therefore angle x equals 85

Orlov [11]3 years ago

4 0

Answer:

85 degrees

Step-by-step explanation:

The sum of the angles of a triangle always add up to 180 degrees.

Here, we have two angles already given, so we can write:

27 + 68 + x = 180

95 + x = 180

Subtract 95 from both sides:

x = 180 - 95 = 85

The answer is thus 85 degrees.

<em>~ an aesthetics lover</em>

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2 years ago

Find the greatest solution for x+y when x^2+y^2 = 7, x^3+y^3=10

damaskus [11]

Answer:

Step-by-step explanation:

set

$f(x,y)=x+y\\$

constrain:

$g(x,y)=x^2+y^2 = 7\\h(x,y)=x^3+y^3=10$

Partial derivatives:

$f_{x}=1\\f_{y} =1 \\g_{x}=2x \\g_{y}=2y\\h_{x}=3x^2 \\h_{y}=3y^2$

Lagrange multiplier:

$grad(f)=a*grad(g)+b*grad(h)\\$

$\left[\begin{array}{ccc}1\\1\end{array}\right]=a\left[\begin{array}{ccc}2x\\2y\end{array}\right]+b\left[\begin{array}{ccc}3x^2\\3y^2\end{array}\right]$

4 equations:

$1=2ax+3bx^2\\1=2ay+3by^2\\x^2+y^2=7\\x^3+y^3=10$

By solving:

$a=4/9\\b=-2/27\\x+y=4$

Second mathod:

Solve for x^2+y^2 = 7, x^3+y^3=10 first:

$x=\frac{1}{2} -\frac{\sqrt{13}}{2} \ or \ y=\frac{1}{2} +\frac{\sqrt{13}}{2} \\x=\frac{1}{2} +\frac{\sqrt{13}}{2} \ or \ y=\frac{1}{2} -\frac{\sqrt{13}}{2} \\x+y=-5\ or\ 1 \or\ 4$