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Brut [27]
3 years ago
14

What is the domain and range of the relation shown in the table?

Mathematics
1 answer:
TEA [102]3 years ago
6 0

Answer:

<u>domain: {10,15,19,32}</u>

<u>range:{5,9,-1}</u>

Step-by-step explanation:

  • As we know domain is the values of input and range is the values of output.
  • Here , x is the input and y is the output.
  • \left[\begin{array}{cc}x&y\\10&5\\15&9\\19&-1\\32&5\end{array}\right]
  • Thus the input values according to the given problem is : 10 ,15 , 19, and thus ,

⇒<em>The domain would accordingly be these four numbers : 10 , 15 , 19 , 32.</em>

  • <u>Note that we donot have any information regarding the other values of x.</u>
  • The range is : { 5,9,-1 } only as the 5 is repeated in two cases .
  • Range is unique and there must be not repetition. Thus the apt answer would be :

<em>domain: {10,15,19,32}</em>

<em>range:{5,9,-1}</em>

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The height of the ball initially is 54 inches. The common ratio has been provided which is 0.750.

The explicit formular for the geometric sequence is shown as;

\begin{gathered} ar^{n-1} \\ \text{Where a is the first term in the sequence,} \\ r\text{ is the common ratio betw}een\text{ every successive term} \\ \text{And n is the nth term} \\ \text{The explicit formular for the height of the ball on the 10th bounce is;} \\ ar^{n-1} \\ 54\times(0.750)^{10-1} \\ 54\times(0.750)^9 \\ 54\times0.07508468\ldots \\ 4.0545 \end{gathered}

The explicit formula is shown as;

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The rest is simply to solve for the height on the 10th bounce

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