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Anna11 [10]
3 years ago
10

A refrigerator has a volume given by the trinomial y^3 + 5y^2 – 14y. What are the possible dimensions of the refrigerator? Use f

actoring.
Mathematics
1 answer:
Elza [17]3 years ago
7 0
Y^3+5y^2-14y

y(y^2+5y-14)

y(y^2+7y-2y-14)

y(y(y+7)-2(y+7))

y(y-2)(y+7)

So there are infinite solutions with the only restriction being that y>2 as V>0
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Lee works for a company that ships packages and must measure the size of each box that needs to be shipped. Lee measures a box a
expeople1 [14]

Answer: 1852.5 cubic inches


Step-by-step explanation:

The Volume of cuboidal box is given by:-

Volume=length\times width\times\ height

Given: The length of box =9\frac{1}{2}\ inches=\frac{19}{2}\ inches

The width of the box =15\ inches

The height of the box =13\ inches

Now, the volume of box is given by:-

Volume=\frac{19}{2}\times15\times13=\frac{3705}{2}=1852.5\ inches^3

3 0
3 years ago
Two cylindrical cans have the same volume. the height of one can is triple the height of the other. if the radius of the narrowe
Tju [1.3M]
Find the attachment below....

7 0
3 years ago
A sand wedge normally costs 65.00. It is on sale for 20% off the regular price. what is the discount
r-ruslan [8.4K]

Answer:$52.00

Step-by-step explanation:

5 0
2 years ago
i have been trying to solve this compound and double angle question please help me find the answer to these question guys​
natali 33 [55]

Answer:

These type of questions are super tricky b/c you have to remember all the different versions of the identities, and then they put the question in some odd form,  I feel like this should land math professors in jail , for dishonesty , b/c it's really a form of "how tricky can I make a question and still have a way to solve it"   anyway,

Step-by-step explanation:

a)

next the question asks   1-cos 2A   and this is total abuse of notation.   the way this should be written is   1- cos( 2A)  so we know that the A is part of the cosine functions input... btw.. in any computer program,  it would never ever let you get away with that top form of the expression.  :/   anyway... I keep ranting.. huh... sorry  :P

1-cos(2A) is an odd form of the identity  1/2(1-cos(2A) = sin^{2}(A)  the 1/2 is missing but we can add that pretty easy, we just have to remember to take it out too. I usually forget to do that. and my professor marks me off completely,  totally wrong, but I just miss one small thing  :/  anyway....

our 1-cos(2A) needs the 1/2 added to it.  or if we move that 1/2 to the other side it looks like  2*sin^{2}(A)  = 1-cos(2A)  and this is that "odd" from of the identity that I was talking about.  

next let's deal with sin(2A)  it has an identity of  2 sin(A)cos(A) which is really nice for us b/c it will cancel out the 2 in then numerator for us, nice !

now our fraction looks like  [2* sin^{2}(A)] / 2 sin(A)cos(A)

so cancel out one of the sines

2*sin(A) / 2 cos(A)

cancel the 2s

Sin(A) / Cos(A) = Tan(A)

nice  it worked out  :P

b)

by the above that we just worked out, then

Tan(15) = Sin(15) / Cos(15)

I had to look up what sin of 15 is b/c it's not one of those special angles but it does have an exact form of

Sin(15) = (√3 - 1) / 2√2

Cos(A) = (√3 + 1) / 2√2

you can use rule of Cos(A-B) = Cos(A)Cos(B)+Sin(A)Sin(B) to get the above and a similar rule for Sin(A-B)

back to our problem,  the 2√2 will cancel out

then we have

Tan(15) =  (√3 - 1) /(√3 + 1)

in the form that is above that's exact, the roots could be approximated but i'll just leave that in the form that is exact.  Most math professors like that form.  

 

4 0
2 years ago
Please can someone help?
Alina [70]

Step-by-step explanation:

R = 6.5cm and r = 2.3 cm

area of the shaded region = area of the outer circle - area of the inner circle

= πR²-πr²

=π(R²-r²)

=π{(6.5)²-(2.3)²}

=π (42.25-5.29)

= 3.14× 36.96

= 115.866

= 116 cm²

6 0
3 years ago
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