X = (15 - 8y)/9
-5[(15 - 8y)/9] + 12y = -107
(-75/9) + (40/9) + 12y = -107
y = -8.59
x = [15 - 8(-8.59)]/9
x = 9.3
(x,y) = (9.3, -8.59)
Total cost = $13.05 + 10.26
= $23.31
Indivdual pay = $23.31 / 3
= $7.77 each
Answer:
42.22% probability that the weight is between 31 and 35 pounds
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean 
and standard deviation 
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
What is the probability that the weight is between 31 and 35 pounds
This is the pvalue of Z when X = 35 subtracted by the pvalue of Z when X = 31. So
X = 35
has a pvalue of 0.5557
X = 31
has a pvalue of 0.1335
0.5557 - 0.1335 = 0.4222
42.22% probability that the weight is between 31 and 35 pounds
Answer:
65 square units
Step-by-step explanation:
The base of the pyramid is 5 by 5 , surface area is 25 square units.
the side of each one is 4 units "high" and 5 long at the base and to find the are of a triangle you multiple base times height then dived by 2. Therefore each side of the triangle is 10 units square. You have 4 sides so...
40 (total of all the sides ) +25 ( base ) = 65
Answer:
SITE A
Step-by-step explanation:
Given :
proposed-site Area-Served
1 2 3 4
A 5.2 4.4 3.6 6.5
B 6.0 7.4 3.4 4.0
C 5.8 5.9 5.9 5.8
D 4.3 4.8 6.5 5.1
Area 1 2 3 4
Number-runs 150 65 175 92
Computing the weighted average for the 4 sites :
Site A:
((150*5.2) + (65*4.4) + (175*3.6) + (92*6.5)) / (150 + 65 + 175 + 92)
= 2294 / 482
= 4.7593
Site B:
((150*6.0) + (65*7.4) + (175*3.4) + (92*4.0)) / (150 + 65 + 175 + 92)
= 2344/ 482
= 4.863
Site C:
((150*5.8) + (65*5.9) + (175*5.9) + (92*5.8)) / (150 + 65 + 175 + 92)
= 2819.6/ 482
= 5.850
Site D:
((150*4.3) + (65*4.8) + (175*6.5) + (92*5.1)) / (150 + 65 + 175 + 92)
= 2563.7/ 482
= 5.319
From the weighted average response time computed for the different sites ;
The best location for the emergency facility would be one with the least average response time; which is SITE A.
