Ok so we need to set the bottom to 0 to find the vertical asympyotes. This becomes x^2 - 4 = 0. Since we're talking about asymptotes, i'll assume you can solve basic equations. Solving for x and you get x = ±2. This means the vertical asymptotes are at ±2. To solve for horizontal asymptotes you take the limit as x goes to ±∞. Either way you end up with ±∞/∞. Now this isn't 1 because they grow at different rates. You differentiate both the top and bottom(L'hopital) and you get 6x/2x which becomes 3. This means the horizontal asymptote is at y = 3.
Step-by-step explanation:
I'm not sure if I'm correct but I think that the difference is that op goes from left to right on the line so it's positive and po goes from right to left so it's negative. Hope I'm correct
Answer: slope = 6
Step-by-step explanation: Your y’s are increasing by 12, while the x’s are increasing by 2. Therefore using rise/run, 12/2 = 6.
4,8,12,16
this is an arithmetic sequence with a common difference of 4. This means u have to add 4 to each term to find the next number
an = a1 + (n - 1) * d
a1 = first term = 4
d = common difference = 4
so ur formula is : an = 4 + (n - 1) * 4 <==
If noone gives you the right answer try using wolfram alpha
