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3 years ago

Fractions greater than 1

Mathematics

2 answers:

fenix001 [56]3 years ago

7 0

Answers may vary, there are several answers.

hammer [34]3 years ago

4 0

There is unlimited possibility’s to that question

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Amelia wants to rearrange the furniture in her room. She makes a scale drawing of her rectangular room,

vovangra [49]

Answer:

The other side = 13 feets long

Step-by-step explanation:

Given that :

Scale of drawing : 2 inches represents 5 feets

Area of rectangular room according to scale drawing = 24.96 in²

Length of one side of the room = 12 feets

Length of other side = x

Area of rectangle = Length * width

If :

2 inches = 5 feets

x = 12 feets

x = (12 *2) / 5

x = 4.8 inches

Hence,

For the scaled drawing :

4.8 * width = 24.96

Width = 24.96 / 4.8

Width = 5.2 inches

Converting to feets according to scale:

2 inches = 5 feets

5.2 inches = x feets

x = (5.2 * 5 ) / 2

x = 13 feets

Other side is 13 feets long

4 0

3 years ago

Eight less thsn a number divided by three is twelve equation pleaseeee

EleoNora [17]

(X/3) - 8 = 12

X being a number divided by 3. This part in parentheses so you solve it first. Subtract 8 from that and your answer equals 12.

6 0

3 years ago

PLEASE HELP QUICKLY!!

choli [55]

Answer:

By excluding (10, 15), a better description can be given for the data set.

Step-by-step explanation:

Overall, this data seems to suggest a decreasing trend. The value (10, 15) is an outlier; if we remove it, the trend appears to be stronger. Thus if we exclude this value we can give a better description of the data set.

6 0

3 years ago

Read 2 more answers

Jenny and Natalie are selling cheesecakes for a school fundraiser. Customers can buy chocolate cakes and vanilla cakes. Jenny so

IrinaVladis [17]

The cost of 1 chocolate cake is $ 6 and cost of 1 vanilla cake is $ 7

Solution:

Let "c" be the cost of 1 chocolate cake

Let "v" be the cost of 1 vanilla cake

Jenny sold 14 chocolate cakes and 5 vanilla cakes for 119 dollars

Therefore, we can frame a equation as:

14 x cost of 1 chocolate cake + 5 x cost of 1 vanilla cake = 119

$14 \times c + 5 \times v=119$

14c + 5v = 119 ------- eqn 1

Natalie sold 10 chocolate cakes and 10 vanilla cakes for 130 dollars

Therefore, we can frame a equation as:

10 x cost of 1 chocolate cake + 10 x cost of 1 vanilla cake = 130

$10 \times c + 10 \times v = 130$

10c + 10v = 130 -------- eqn 2

Let us solve eqn 1 and eqn 2

Multiply eqn 1 by 2

28c + 10v = 238 ------ eqn 3

Subtract eqn 2 from eqn 3

28c + 10v = 238

10c + 10v = 130

( - ) --------------------------

18c = 108

c = 6

Substitute c = 6 in eqn 1

14(6) + 5v = 119

84 + 5v = 119

5v = 119 - 84

5v = 35

v = 7

Thus cost of 1 chocolate cake is $ 6 and cost of 1 vanilla cake is $ 7

8 0

3 years ago

Follow the process of completing the square to solve 2x2 + 8x - 12 = 0.

Rom4ik [11]

Please: Use "^" to denote exponentiation: 2x^2 + 8x - 12 = 0

Reduce this by div. every term by 2: x^2 + 4x - 6 = 0

Here a=1, b=4 and c = -6. Square half of b, obtaining (4/2)^2 = 4, and add, and then subtract, this 4 to x^2 + 4x - 6:

 x^2 + 4x +4 - 4 - 6 = 0. Rewrite the square as (x+2)^2, obtaining new equation

(x+2)^2 = 10. Take the sqrt of both sides: x+2 = plus or minus sqrt(10).

Finally, solve for x: x = -2 plus or minus sqrt(10).

8 0

3 years ago