3 years ago

Explain how you would show 135% on a 10-by10 grid

Mathematics

1 answer:

dangina [55]3 years ago

8 0

You would shade in 135 of the squares in the grid(s)

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guajiro [1.7K]

The anwser is c your welcome

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2 years ago

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X^2+y^2+14x+10y=7 <br> center and radius

Sholpan [36]

$(x-a)^2+(y-b)^2=r^2\\\\(a;\ b)-the\ coordinates\ of\ the\ center\\r-the\ radius\\\\==================================\\Use:(k+l)^2=k^2+2kl+l^2\ (*)\\==================================$

$x^2+y^2+14x+10y=7\\\\x^2+14x+y^2+10y=7\\\\x^2+2x\cdot7+y^2+2y\cdot5=7\\\\\underbrace{x^2+2x\cdot7+7^2}_{Use\ (*)}-7^2+\underbrace{y^2+2y\cdot5+5^2}_{Use\ (*)}-5^2=7\\\\(x+7)^2-49+(y+5)^2-25=7\\\\(x+7)^2+(y+5)^2-74=7\ \ \ \ |add\ 74\ to\both\ sides\\\\(x+7)^2+(y+5)^2=81\\\\(x+7)^2+(y+5)^2=9^2$

$Answer:\\\boxed{(-7;-5)-center;\ 9-radius}$

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3 years ago

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How to prove this using trig identities?

Pavlova-9 [17]

Step-by-step explanation:

tanB + cotB = (sinB)/(cosB) + (cosB)/(sinB)

= (sin2B + cos2B)/[(cosB)(sinB)]

= 1/[(cosB)(sinB)]

= (1/cosB)(1/sinB)

= (secB)(cscB)

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