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Tags: <em>sine sin common angles trig trigonometry </em>
Answer:
Part A: 1 solution
Part B:
3(2x-7)=3
6x-21=3
+21 +21
6x=24
/6 /6
x=4
Step-by-step explanation:
First you <u>distribute 3(2x-7)=3</u> to 6x-21=3. Next you do inverse operations by <u>adding 21 to both sides</u> of the equation to get 6x=24. Finally you <u>divide both sides by 6</u> to get x=4
Answer:
-84, -71, -58, -45, -32, -19
Step-by-step explanation:
Yes she does have enough. Here is why:
If you add 1/4 and 1/4, you get 2/8 which is also 1/2.
3/4 is bigger than one half. If you subtract 1/2 from 3/4, you get 1/4.
So she would have 1/4 left.
Absolutely enough to get to her friends house and back. :)
Answer:
Step-by-step explanation:
Find the multiples of 2x^2 and 2
for 2x^ you get 2,1 but they need to have x to get x^2 so; (2x and x)=2x^2
for 2 you get 2,1 (2x1)=2
Because your equation has a 5x and no negatives you know that your factors need to be positive.
(2x+1)(x+2)
when you multiply these you get
2x^2+4x+x+2 (remember 2x multiplies with everything inside (x+2) = 2x^2+4) and so on for the x (x+2) =x+2 )
Then you combine like terms 4x+x=5x
and those are the only like terms available and you get
2x^2+5x+2
Hope it helped
