Answer:
elasticity supply of dog food = 2.61
elasticity supply of cat food = 1.71
Step-by-step explanation:
The midpoint formula for elasticity is:
![Elasticity = \frac{(Q2-Q1)/[(Q2+Q1)/2]}{(P2-P1)/[(P2+P1)/2]}](https://tex.z-dn.net/?f=Elasticity%20%3D%20%5Cfrac%7B%28Q2-Q1%29%2F%5B%28Q2%2BQ1%29%2F2%5D%7D%7B%28P2-P1%29%2F%5B%28P2%2BP1%29%2F2%5D%7D)
Point 1: Q = 39.0 and P = 5.50
Point 2: Q = 101.0 and P = 7.75
![Elasticity\ supply\ of\ dog\ food = \frac{(101.0-39.0)/[101.0+39.0)/2]}{(7.75-5.50)/[(7.75+5.50)/2]}=2.61](https://tex.z-dn.net/?f=Elasticity%5C%20supply%5C%20of%5C%20dog%5C%20food%20%3D%20%5Cfrac%7B%28101.0-39.0%29%2F%5B101.0%2B39.0%29%2F2%5D%7D%7B%287.75-5.50%29%2F%5B%287.75%2B5.50%29%2F2%5D%7D%3D2.61)
Doing the same for the cat food:
![Elasticity\ supply\ of\ cat\ food = \frac{(71.0-39.0)/[71.0+39.0)/2]}{(7.75-5.50)/[(7.75+5.50)/2]}=1.71](https://tex.z-dn.net/?f=Elasticity%5C%20supply%5C%20of%5C%20cat%5C%20food%20%3D%20%5Cfrac%7B%2871.0-39.0%29%2F%5B71.0%2B39.0%29%2F2%5D%7D%7B%287.75-5.50%29%2F%5B%287.75%2B5.50%29%2F2%5D%7D%3D1.71)
y=5/3x-6 written in standard form using integers is 5/3x + y = -6
Answer: 5/3x + y = -6
live
Lateral surface are = 2( 1/2 x 11 x 11.9) + 2( 1/2 x 9 x 12.3)
Lateral surface area = 130.9 + 110.7 = 241.6 ft²
Answer: 241.6 ft² (Answer C)
So all u have to do is say all the x values that have a point (the domain) and all the y values that have a point (the range). If it is continuous, like a line, then u say all the points between two points. For example the range of the bottom right is [-1,5]. If it goes to infinity or negative infinity, you say something like (-infinity,infinity). With the sideways 8 of course. Btw, (-infinity, infinity) is the domain of the bottom right ;D
Answer:
A. 5
Step-by-step explanation:
because 13 is the hypotenuse and 8 is the sine
