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den301095 [7]
2 years ago
13

A rectangle has a width of w . Its length is 4 more than twice the width. what is the area

Mathematics
1 answer:
vredina [299]2 years ago
8 0

Answer:

if the width is W and the length is 4 more of twice the width therefore the length is 2W+4

area = length × width

= 2W+4×W

=2W+4

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Amaya used these steps to solve the equation 8x + 4 = 9 + 4 (2x-1). Which choice describes the meaning of her result, 4=5?
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1) Determine the discriminant of the 2nd degree equation below:
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\LARGE{ \boxed{ \mathbb{ \color{purple}{SOLUTION:}}}}

We have, Discriminant formula for finding roots:

\large{ \boxed{ \rm{x =  \frac{  - b \pm \:  \sqrt{ {b}^{2}  - 4ac} }{2a} }}}

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1) Given,

3x^2 - 2x - 1

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➝ D = 4 + 12

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2) Solving by using Bhaskar formula,

❒ p(x) = x^2 + 5x + 6 = 0

\large{ \rm{ \longrightarrow \: x =  \dfrac{ - 5\pm  \sqrt{( - 5) {}^{2} - 4 \times 1 \times 6 }} {2 \times 1}}}

\large{ \rm{ \longrightarrow \: x =  \dfrac{ - 5  \pm  \sqrt{25 - 24} }{2 \times 1} }}

\large{ \rm{ \longrightarrow \: x =  \dfrac{ - 5 \pm 1}{2} }}

So here,

\large{\boxed{ \rm{ \longrightarrow \: x =  - 2 \: or  - 3}}}

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\large{ \rm{ \longrightarrow \: x =  \dfrac{  - 2 \pm  \sqrt{ {2}^{2}  - 4 \times 1 \times 1} }{2 \times 1} }}

\large{ \rm{ \longrightarrow \: x =  \dfrac{ - 2 \pm \sqrt{4 - 4} }{2} }}

\large{ \rm{ \longrightarrow \: x =  \dfrac{ - 2 \pm 0}{2} }}

So here,

\large{\boxed{ \rm{ \longrightarrow \: x =  - 1 \: or \:  - 1}}}

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\large{ \rm{ \longrightarrow \: x =  \dfrac{ - ( - 1) \pm  \sqrt{( - 1) {}^{2} - 4 \times 1 \times ( - 20) } }{2 \times 1} }}

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\large{ \rm{ \longrightarrow \: x =  \dfrac{1 \pm 9}{2} }}

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\large{\boxed{ \rm{ \longrightarrow \: x = 4 \: or \:  - 1}}}

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