Answer:
See the explanation.
Step-by-step explanation:
We are given the function f(x) = x² + 2x - 5
Zeros :
If f(x) = 0 i.e. x² + 2x - 5 = 0
The left hand side can not be factorized. Hence, use Sridhar Acharya formula and
and
⇒ x = -3.45 and 1.45
Y- intercept :
Putting x = 0, we get, f(x) = - 5, Hence, y-intercept is -5.
Maximum point :
Not defined
Minimum point:
The equation can be expressed as (x + 1)² = (y + 5)
This is an equation of parabola having the vertex at (-1,-5) and axis parallel to + y-axis
Therefore, the minimum point is (-1,-5)
Domain :
x can be any real number
Range:
f(x) ≥ - 6
Interval of increase:
Since this is a parabola having the vertex at (-1,-5) and axis parallel to + y-axis.
Therefore, interval of increase is +∞ > x > -1
Interval of decrease:
-∞ < x < -1
End behavior :
So, as x tends to +∞ , then f(x) tends to +∞
And as x tends to -∞, then f(x) tends to +∞. (Answer)
12 - 2x = -2(y - x)
12 - 2x = -2y - (-2x)
12 - 2x = -2y + 2x
12 - 2x - 2x = -2y + 2x - 2x
12 - 4x = -2y
12 - 12 - 4x = -2y - 12
-4x = -2y - 12
-4x/4 = -2y/4 - 12/4
-x = -0.5y - 3
-x/-1 = -0.5y/-1 - 3/-1
x = 0.5y + 3
or
x = 3 + 0.5y
Answer
Factor 13 out of 26x+13
= 13( 2x+1)
Answer:
Step-by-step explanation:
Given that a parking lot has two entrances. Cars arrive at entrance I according to a Poisson distribution at an average of 3 per hour and at entrance II according to a Poisson distribution at an average of 2 per hour.
Assuming the number of cars arriving at the two parking lots are independent we have total number of cars arriving X is Poisson with parameter 3+2 = 5
X is Poisson with mean = 5
the probability that a total of 3 cars will arrive at the parking lot in a given hour
= P(X=3) = 0.1404
b) the probability that less than 3 cars will arrive at the parking lot in a given hour
= P(X<3)
= P(0)+P(1)+P(2)
= 0.1247
Answer:
10.5 I think
Step-by-step explanation:
(1/2) *12 is 6
(1/2)*21 is 10.5
