Step-by-step explanation:
It is given that,
The length of section 1 is 0.75 m and the length of section 2 is 15/100 m. The total length of the section is equal to the sum of section 1 and section 2. So, we will add them as follows :
So, the length of the section is 0.9 m or 9/10 m
The reliability of a two-component product if the components are in parallel is 0.99.
In this question,
The probability of failure-free operation of a system with several parallel elements is always higher than that of the best element in the system. Reliability can be increased if the same function is done by two or more elements arranged in parallel.
A system contains two components that are arranged in parallel, they are 0.95 and 0.80.
Therefore the system reliability can be calculated as follows
⇒ 1 - ( 1 - 0.95 ) × ( 1 - 0.80 )
⇒ 1 - (0.05 × 0.20)
⇒ 1 - 0.01
⇒ 0.99
Hence we can conclude that the reliability of a two-component product if the components are in parallel is 0.99.
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Answer:
Population after 4 years = 49 (nearest unit)
Population after 5 years = 47 (nearest unit)
Step-by-step explanation:
Yearly decrease = 4.6%
Decrease factor (what's left) = (100-4.6)% = 0.954
Current population, P = 60
population after n years = P(0.954)^n (to the nearest unit)
Population after 4 years = 60(0.954)^4 = 49.7 = 49 (nearest unit)
Population after 5 years = 60(0.954)^5 = 47.4 = 47 (nearest unit)
41.803 is 42 rounded to the nearest whole number because when you go past .5 you round to the nearest highest number, but when your below .5 then you round to the nearest lowest number.
Factor out the GCF first
3(2x² - x - 10)
3(2x - 5)(x + 2)
