This is how you solve it; but first of all convert the percent into a decimal;55%= 0.55

0.55x = 164 (divide by 0.55 on both sides)
x = 164/0.55
x = 298.18 (rounded to the nearest hundredth)
so 164 is 55% of 298.18(rounded)

8 0

3 years ago

Two fair dice are rolled 3 times and the sum of the numbers that come up is recorded. Find the probability of these events. a. T

alexandr402 [8]

Answer:

Step-by-step explanation:

Given that two fair dice are rolled 3 times and the sum of the numbers that come up is recorded.

a) The sum is 4 on each of the three rolls.

(1,3) (2,2) (3,1) HEnce for one throw prob = 3/36 =1/12

Prob for getting same sum 4 in 3 rolls = $(\frac{1}{12} )^3$

(since each trial is independent)

b) Prob sum =4 in exactly 2 rolls

= $3C2 (1/12)^2 (11/12)$ = $\frac{33}{12^3}$

5 0

2 years ago