We have the zeroes of this function:
x 1 = 2, x 2 = - 1, x 3 = - 5
Polynomial of least degree is in form:
p ( x ) = a x³ + b x² + c x + d
Three factors of the polynomial are:
( x - x1 ) * ( x - x2 ) * ( x - x3 ) =
= ( x - 2 ) · ( x + 1 ) · ( x + 5 ) =
= ( x² + x - 2 x - 2 ) · ( x + 5 ) =
= ( x² - x - 2 ) · ( x + 5 ) =
= x³ + 5 x² - x² - 5 x - 2 x - 10 = x³ + 4 x² - 7 x - 10
Answer: The polynomial of least degree with integer coefficients is:
p ( x ) = x³ + 4 x² - 7 x - 10.
1) equation given: 0 = x^2 - 6x + 4
2) transpose 4: - 4 = x^2 - 6x
3) complete squares: - 4 = (x^2 - 6x + 9) - 9
4) transpose -9 and factor the square trinomial x^2 - 6x + 9:
- 4 + 9 = (x - 3)^2
5) combine like terms: 5 = (x - 3)^2
6) take square root on both sides: x - 3 = +/- √5
7) transpose - 3: x = 3 +/- √5
Answer: the two solutions are x = 3 - √5 and x = 3 + √5
Answer:
(1;1)
Step-by-step explanation:
1. if y=2x-1, then it is possible to substitute 2x-1 into the 2d equation:
5x-4(2x-1)=1, ⇒ 5x-8x+4=1, ⇔ -3x=-3, ⇔ x= 1;
2. if x=1, then y=2x-1=2-1= 1.
3. the required pair is (1;1)
Answer:
Well i am not sure on that but i do know that the angle measures have to add up to 180 degrees hope that helps at least a little
Step-by-step explanation: