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sleet_krkn [62]
3 years ago
15

For question number 1, would the data be closer to 10 or 14?

Mathematics
1 answer:
Ulleksa [173]3 years ago
8 0
The answer is 14
Hope this helps
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if the point (-4,5) and (0,2) are used to find the slope of the line the slope is -3/4 what is the slope if the points (0,2) and
wariber [46]
The slope will be -3/4
To find slope you just place the change in y over the change in x.
2- -1=3
0-4= -4
The slope is -3/4 which is the same as before
7 0
3 years ago
Triangle ABC has vertices at A(-2,1), B(-2,-3), and C(1,-2). What is the area of the triangle? a 18 square units b 9 square unit
natka813 [3]

Answer:

Option C. 6 square units

Step-by-step explanation:

we know that

Heron's Formula is a method for calculating the area of a triangle when you know the lengths of all three sides.  

Let  

a,b,c be the lengths of the sides of a triangle.  

The area is given by:

A=\sqrt{p(p-a)(p-b)(p-c)}

where

p is half the perimeter

p=\frac{a+b+c}{2}

we have

Triangle ABC has vertices at A(-2,1), B(-2,-3), and C(1,-2)

the formula to calculate the distance between two points is equal to

d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}

step 1

Find the distance AB

d=\sqrt{(-3-1)^{2}+(-2+2)^{2}}

d=\sqrt{(-4)^{2}+(0)^{2}}

dAB=4\ units

step 2

Find the distance BC

d=\sqrt{(-2+3)^{2}+(1+2)^{2}}

d=\sqrt{(1)^{2}+(3)^{2}}

dBC=\sqrt{10}\ units

step 3

Find the distance AC

d=\sqrt{(-2-1)^{2}+(1+2)^{2}}

d=\sqrt{(-3)^{2}+(3)^{2}}

dBC=\sqrt{18}\ units

step 4

a=AB=4\ units

b=BC=\sqrt{10}\ units

c=AC=\sqrt{18}\ units

Find the half perimeter p

p=\frac{4+\sqrt{10}+\sqrt{18}}{2}=5.70\ units

Find the area

A=\sqrt{5.7(5.7-4)(5.7-3.16)(5.7-4.24)}

A=\sqrt{5.7(1.7)(2.54)(1.46)}

A=\sqrt{35.93}

A=6\ units^{2}

7 0
3 years ago
Numbers 6,7,8 I can't figure out
marysya [2.9K]
6. Take your compass and place the pointed edge on point B. Place one point on each side of B, each the same distance away from B. Next, place your compass on one of the two new points and extend your compass to draw a circle. Repeat with the SAME radian from the other point. Find where the two circles intersect with each other and draw a line from the points of intersection to point B. Place point A anywhere on that line that you just created and then you're done!

7. Select any place along either line and place point S on it. Next, using the same method as above, draw two circles with the same radius around both points S and R. Draw a line through the intersection points. Locate the intersection where your new line connects with the line across from the shared line of RS. Place a point at the intersection, for your reference, then connect that point to point S. Now you have completed this problem as well.

8. Use a straight edge to draw one line. Place points A and B on each end. Use the circle method yet again to find a line perpendicular to line AB. Next, take your compass and set it to the distance from point A to B. Use that same distance to make a point on the perpendicular line. This creates point C. The final step is to connect A with C and B with C.
7 0
3 years ago
Describe how a point on a graph is related to a table and an equation that represent the same relationship.
castortr0y [4]

Answer:

because everything is relative to each other.

Step-by-step explanation: Graphing ordered pairs is only the beginning of the story. Once you know how to place points on a grid, you can use them to make sense of all kinds of mathematical relationships. A linear relationship is a relationship between variables such that when plotted on a coordinate plane, the points lie on a line. Let’s start by looking at a series of points in Quadrant I on the coordinate plane. Look at the five ordered pairs (and their x– and y-coordinates) below.

4 0
3 years ago
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The eatery restaurant has 200 tables. On a recent evening there were reservations for 1/10 of the tables. How many tables were r
lbvjy [14]
20 the answer for this is 20
3 0
3 years ago
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