Question

Consider rectangle PQRS (not shown) with PQ=12 and PS=16. If A and B are the midpoints of sides PQ?????? and QR?????? respectively, find AB.

Answer 1

Answer: The answer is AB =10

Step-by-step explanation:

In the given figure there is a rectangle PQRS

Given :PQ=12

PS=16

Since it is a rectangle

∵ PQ=RS

and PS=QR

i.e. QR=16

A is mid point of PQ

⇒QA =$\frac{12}{2}$

=6

B is mid point of QR

⇒ QB=$\frac{16}{2}$

=8

So In Δ AQB

Applying pythagoras theorem

AQ² +BQ² =AB²

∵ AB²=6²+8²

=36 +64

=100

i.e. AB=√100

=10