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Svetach [21]
3 years ago
9

Help me solve 10 and 11 Please. And show your work

Mathematics
1 answer:
Vaselesa [24]3 years ago
5 0
I'm sorry idk how to do it
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Plz help I need help plz
Nutka1998 [239]

Answer:

associative! property! of! addition!

Step-by-step explanation:

we change the order of the addends but the sum doesn't change

8 0
2 years ago
Read 2 more answers
Consider event A and event B. What is the probability that event B occurs, given that event A has already occurred?
sashaice [31]
P(B|A) = P(B), based on your description, it does not indicate any relationship between A and B, so P(B) is irrelevant with P(A)
5 0
2 years ago
Read 2 more answers
A peach orchard owner wants to maximize the amount of peaches produced by her orchard.
qaws [65]

Answer:

  a) Y(x) = {900, x≤30; 900-40(x-30), x>30}

  b) T(x) = {900x, x≤30; 2100x-40x², x>30}

  c) dT/dx = {900, x≤30; 2100-80x, x>30}

Step-by-step explanation:

a) The problem statement gives the function for x ≤ 30, and gives an example of evaluating the function for x = 35. So, replacing 35 in the example with x gives the function definition for x > 30.

\displaystyle Y(x)=\left\{\begin{array}{lcl}900&\text{for}&x\le 30\\900-40(x-30)&\text{for}&x>30\end{array}\right.

__

b) The yield per acre is the product of the number of trees and the yield per tree:

  T(x) = x·Y(x)

\displaystyle T(x)=\left \{\begin{array}{lcl}900x&\text{for}&x\le 30\\2100x-40x^2& \text{for}&x>30\end{array}\right.

__

c) The derivative is ...

\displaystyle\frac{dT}{dx}=\left \{\begin{array}{lcl}900&\text{for}&x\le 30\\2100-80x& \text{for}&x>30\end{array}\right.

_____

The attached graph shows the yield per acre (purple, overlaid by red for x<30), the total yield (black), and the derivative of the total yield (red). You will note the discontinuity in the derivative at x=30, where adding one more tree per acre suddenly makes the rate of change of yield be negative.

6 0
3 years ago
What 2 numbers add to get 2 and multiply to 4
rusak2 [61]
Factor 4
4=1 times 4
2 times 2
they don't add to 2
set up equation
x+y=2
xy=4

first equation, subtract x from both sides
y=2-x
subsitute for y
x(2-x)=4
distribute
2x-x^2=4
add x^2
2x=x^2+4
subtract 2x
0=x^2-2x+4
use quadratic formula which is
if you have ax^2+bx+c=0 then
x=\frac{ -b+/-\sqrt{b^{2}-4ac} }{2a} so

1x^2-2x+4=0
a=1
b=-2
c=4
x=\frac{ -(-2)+/-\sqrt{(-2)^{2}-4(1)(4)} }{2(1)}
x=\frac{ 2+/-\sqrt{4-16} }{2}
x=\frac{ 2+/-\sqrt{-12} }{2}
we have \sqrt{-12} and that doesn't give a real solution
therefor there are no real solutions
but if you want to solve fully
x=\frac{ 2+/-2\sqrt{-3} }{2}
i=\sqrt{-1}
x=\frac{ 2+/-2i\sqrt{3} }{2}
x=1+/-i\sqrt{3}
x=1-i\sqrt{3} or x=1+i\sqrt{3} (those are the 2 numbers)

 





6 0
3 years ago
It takes 10 road workers 5 days to complete a road repair when working 2 hours a day. Working at the same pace, how many days wi
Levart [38]

Answer:

10 days

Step-by-step explanation:

10 workers work 2 hrs a day for 5 days, so the work content is 10*5*2=100 manhours.

2 people work 5 hrs a day, so they deliver 10 manhours a day. To finish a work of 100 manhours,they’ll need 100/10=10 days.

The answer is 10 days.

6 0
2 years ago
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