Answer:
<h2>x = 2</h2>
Step-by-step explanation:
Look at the picture.
It is negatively skewed to the right
Answer:
No Solutions
Step-by-step explanation:
<span> I am assuming you want to prove:
csc(x)/[1 - cos(x)] = [1 + cos(x)]/sin^3(x).
</span>
<span>If we multiply the LHS by [1 + cos(x)]/[1 + cos(x)], we get:
LHS = csc(x)/[1 - cos(x)]
= {csc(x)[1 + cos(x)]/{[1 + cos(x)][1 - cos(x)]}
= {csc(x)[1 + cos(x)]}/[1 - cos^2(x)], via difference of squares
= {csc(x)[1 + cos(x)]}/sin^2(x), since sin^2(x) = 1 - cos^2(x).
</span>
<span>Then, since csc(x) = 1/sin(x):
LHS = {csc(x)[1 + cos(x)]}/sin^2(x)
= {[1 + cos(x)]/sin(x)}/sin^2(x)
= [1 + cos(x)]/sin^3(x)
= RHS.
</span>
<span>I hope this helps! </span>
Answer:
The answer is a
Step-by-step explanation:
Using point (0,0) and (3,-9)
Slope of the line = -9-0/3-0 = -9/3 = -3
Equation of the line using point (0,0)
y - 0 = -3(x -0)
y= -3x
Hope this helps.
