Ask question

Ask question

All categories

3 years ago

15

What is

5" align="absmiddle" class="latex-formula">
please show how you got the answer

2 answers:

Alchen [17]3 years ago

5 0

Answer: 3.33

Explanation:

I added a picture hope it helps

katovenus [111]3 years ago

4 0

ANSWER: 3.3370212766 all you do is put it in a calculator

You might be interested in

What is the equation to find the circumference of a circle?

Rasek [7]

Answer:

C=2 π r

Step-by-step explanation:

8 0

2 years ago

Read 2 more answers

If you where asked to solve a system of linear equations using the substitution method, what form would one or both of the equat

likoan [24]

Answer:

It's A

Step-by-step explanation:

In general, the equation in point-slope form will give an expression that can substitute for "y", as that form is ...

y = [something]

_____

In specific instances, the other forms of the linear equations may work, but that is not guaranteed.

5 0

2 years ago

Find the slope of a line parallel to y = 1/2x+3

VashaNatasha [74]

Y=mx+b
m=slope

paralell lines have the same slope

y=1/2x+3
m=slope=1/2

the slope of the paralelll line is 1/2

5 0

3 years ago

Use the given triangles to answer the question. (Easy)

kiruha [24]

Answer:

JK≅MN, KL≅NO and ∠K≅∠N

Step-by-step explanation:

we know that

A Reflection is a transformation that doesn't change the size or shape of the figure

so

Triangle JKL and triangle MNO are congruent

The corresponding sides and the corresponding angles are congruent

therefore

JK≅MN, KL≅NO,JL≅MO

and

∠J≅∠M, ∠K≅∠N,∠L≅∠O

8 0

2 years ago

<img src="https://tex.z-dn.net/?f=The%20%5C%3A%20%20value%20%20%5C%3A%20of%20%20%5C%3A%20%20%5Csqrt%7B6%20%2B%20%20%5Csqrt%7B6%2

saul85 [17]

$\large\underline{\sf{Solution-}}$

<u>Let us assume that:</u>

$\sf \longmapsto x = \sqrt{6 + \sqrt{6 + \sqrt{6 + ... \infty } } }$

We can also write it as:

$\sf \longmapsto x = \sqrt{6 + x }$

Squaring both sides, we get:

$\sf \longmapsto {x}^{2} =6 + x$

$\sf \longmapsto {x}^{2} - x - 6 =0$

By splitting the middle term:

$\sf \longmapsto {x}^{2} - 3x + 2x - 6 =0$

$\sf \longmapsto x(x - 3) + 2(x - 3 ) =0$

$\sf \longmapsto (x+ 2)(x - 3 ) =0$

<u>Therefore:</u>

$\longmapsto\begin{cases} \sf (x+ 2) =0 \\ \sf (x - 3) = 0 \end{cases}$

$\sf \longmapsto x = - 2,3$

<u>But x cannot be negative. </u>

$\sf \longmapsto x = 3$

Therefore, the value of the expression is 3.

$\large\underline{\sf{Verification-}}$

Given:

$\sf\longmapsto x=3$

We can also write it as:

$\sf\longmapsto x = \sqrt{9}$

$\sf\longmapsto x = \sqrt{6+3}$

$\sf\longmapsto x = \sqrt{6 + \sqrt{9}}$

$\sf\longmapsto x = \sqrt{6 + \sqrt{6+3}}$

$\sf\longmapsto x = \sqrt{6 + \sqrt{6+\sqrt{9}}}$

$\sf\longmapsto x = \sqrt{6 + \sqrt{6+\sqrt{6+3}}}$

This pattern will continue.

$\sf\longmapsto x = \sqrt{6 + \sqrt{6+\sqrt{6+...\infty}}}$

7 0

2 years ago