Answer:
Step-by-step explanation:
45 = (b(4b - 2))/2
90 = 4b2 - 2b
4b2 - 2b - 90 = 0
(2b + 9)(2b - 10) = 0
2b + 9 = 0
2b = -9
b = -9/2
If we were looking for zeroes, this would be an answer, but since we're looking for measurement, we don't use negative numbers.
90 = 4b2 - 2b
4b2 - 2b - 90 = 0
(2b + 9)(2b - 10) = 0
2b + 9 = 0
2b = -9
b = -9/2
Answer:
Step-by-step explanation:
1.
Equation one:
x = -5, x = -1 (Both are real)
Equation two:
No real solutions
Equation three:
x = -3 (Real)
Equation four:
No real solutions
2.
The easiest way to figure out if an equation has real solutions is to factor it. If it is factorable, then it has real solutions. If it isn't, then it doesn't have real solutions.
Answer:
a b c
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Step-by-step explanation: