How do you work out 85.68/21?

El segmeno JL tiene puntos finales J(-3,-4) y L(7,6). ¿Cuáles son las coordenadas del punto K, de modo que el punto K esté en el

Gekata [30.6K]

I don’t know that answer

7 0

3 years ago

NEED HELP!!!!! ASAP THANK YOU SO MUCH!!!!! What figure is a dilation of Figure A by a factor of 3?

Fynjy0 [20]

Answer:

the figure on the top left

Step-by-step explanation:

Hey There!

If figure a was going to be dilated by a scale factor of 3 you would have to multiply all of its dimensions by 3

the top length would be 6

the bottom length would be 9

the right side length would be 12

and the left side length would be 9

The first figure has all of these dimensions thus it is correct answer

6 0

3 years ago

Which expression can be simplified to find the slope of the trend line in the scatterplot? On a graph, a line goes through point

Igoryamba

Your answer is StartFraction 35 minus 21 Over 8 minus 4 EndFraction → 35–21/8–4

6 0

3 years ago

Read 2 more answers

Lines c and d are intersected by line p. At the intersection of lines c and p, the bottom left angle is (3 x + 45) degrees. At t

anzhelika [568]

Answer:

its 18

Step-by-step explanation:

i just took the test on edg :)

4 0

4 years ago

A manufacturer of a new medication on the market for Alzheimer's disease makes a claim that the medication is effective in 65% o

NeX [460]

Answer:

$z=\frac{0.639 -0.65}{\sqrt{\frac{0.65(1-0.65)}{180}}}=-0.309$

$p_v =P(z$

So the p value obtained was a very high value and using the significance level given $\alpha=0.05$ we have $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the proportion of adults with the medication was effective is not significantly less than 0.65

Step-by-step explanation:

Data given and notation

n=180 represent the random sample taken

X=115 represent the adults with the medication was effective

$\hat p=\frac{115}{180}=0.639$ estimated proportion of adults with the medication was effective

$p_o=0.65$ is the value that we want to test

$\alpha=0.05$ represent the significance level

Confidence=95% or 0.95

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

Concepts and formulas to use

We need to conduct a hypothesis in order to test the claim that true proportion is less than 0.65.:

Null hypothesis: $p \geq 0.65$

Alternative hypothesis: $p < 0.65$

When we conduct a proportion test we need to use the z statisitc, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

Calculate the statistic

Since we have all the info requires we can replace in formula (1) like this:

$z=\frac{0.639 -0.65}{\sqrt{\frac{0.65(1-0.65)}{180}}}=-0.309$

Statistical decision

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The significance level provided $\alpha=0.05$ . The next step would be calculate the p value for this test.

Since is a left tailed test the p value would be:

$p_v =P(z$

So the p value obtained was a very high value and using the significance level given $\alpha=0.05$ we have $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the proportion of adults with the medication was effective is not significantly less than 0.65

3 0

3 years ago