For this case we have that by definition, the roots, or also called zeros, of the quadratic function are those values of x for which the expression is 0.
Then, we must find the roots of:

Where:

We have to:
Substituting we have:

By definition we have to:

So:

Thus, we have two roots:

Answer:

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Answer:
-4/3
Step-by-step explanation:
Slope: (y2-y1)/(x2-x1)
(-5-3)/(-3+9) = -8/6 = -4/3
The slope is -4/3
Answer:
x = 3(6 + y)/2
Step-by-step explanation:
Solving for x
Add 3y to both sides.
2x = 18 + 3y
Divide both sides by 2.
x = 18 + 3y/2
Factor out the common term 3.
x = 3(6 + y)/2
Answer:
x = -2
Step-by-step explanation:
The tangent line has length "x + 8"
The secant line has length "x + 6 + 5", where
5 is the inner part
x + 6 is the outer part
Now,
the secant-tangent theorem tells us that square of the tangent line is equal to the outer segment of secant line multiplied by length of whole secant line.
So, we can say:

We can solve for x shown below:

The value of x is -2