The answer is -8
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Explanation:
There are two ways to get this answer
Method 1 will have us plug x = 0 into h(x) to get
h(x) = x^2 - 4
h(0) = 0^2 - 4
h(0) = 0 - 4
h(0) = -4
Then this output is plugged into g(x) to get
g(x) = 2x
g(-4) = 2*(-4)
g(-4) = -8 which is the answer
This works because (g o h)(0) is the same as g(h(0)). Note how h(0) is replaced with -4
So effectively g(h(0)) = -8 which is the same as (g o h)(0) = -8
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The second method involves a bit algebra first
Start with the outer function g(x). Then replace every x with h(x). On the right side, we will replace h(x) with x^2-4 because h(x) = x^2-4
g(x) = 2x
g(x) = 2( x )
g(h(x)) = 2( h(x) ) ... replace every x with h(x)
g(h(x)) = 2( x^2-4 ) ... replace h(x) on the right side with x^2-4
g(h(x)) = 2x^2-8
(g o h)(x) = 2x^2-8
Now plug in x = 0
(g o h)(x) = 2x^2-8
(g o h)(0) = 2(0)^2-8
(g o h)(0) = 2(0)-8
(g o h)(0) = 0-8
(g o h)(0) = -8
Regardless of which method you use, the answer is -8
It would be 220 rounded to the nearest ten because the number in the ones place does not equal or exceed 5.
So 220 is your answer :)
Answer:
a. connect the point (0 , 3) with A
b. connect the origin (0 , 0) with B
c. For A: y = 0.5x +3
For B: y = 0.5x
Step-by-step explanation:
y = ax + b is the general rule for any straight line
a being the slope and b being the y intercept, a is given to be 0.5
y = 0.5x + b, substitute the coordinates of point A
4 = 0.5 *2 +b hence b = 4 - 0.5 *2 = 4 - 1 = 3
so y = 0.5 x + 3 is the equation of the line passing through A
since the second line that passes through B is parallel to the first, hence it has the same slope of 0.5
same procedure, substitute coordinates of B
2 = 0.5 * 4 + b hence b = 2 - 0.5 *4 = 2 - 2= 0
so y = 0.5 x is the equation of the line passing through B
<h3>
Answer:</h3>
1 27/28 ≈ 1.964 gallons/hour
<h3>
Step-by-step explanation:</h3>
You want gallons in the numerator of your unit rate, but that unit is in the denominator of the mileage rate. So, the computation must involve division by 28 mpg. Hours is already in the denominator of 55 mph, so the computation will involve multiplication by that rate.
... (55 mi/h)/(28 mi/gal) = (55 mi/h)·(1 gal/(28 mi)) = 55/28 gal/h
... = 1 27/28 gal/h
