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Anuta_ua [19.1K]
3 years ago
6

Help one who explains better will get brainliest

Mathematics
2 answers:
chubhunter [2.5K]3 years ago
4 0
1) First way:
The sides that are legs of the trapezoid is parallel, angles 110⁰ and x are opposite interior angles that are congruent. So x=110⁰

2) Second way
Sum of all angles are 360⁰,
So (90+90+110+y)=360
180+110+y=360 (y is the 4th angle in trapezoid)
290+y=360
y=360-290=70
x+y=180
x+70=180
x=110⁰


Savatey [412]3 years ago
3 0
First, you have to find out the missing angle of the quadrilateral. We know that there are two right angles, one angle measuring 110° degrees, and that all the angles must add up to 360°.
We can use the equation
90+90+110+x=360
290+x=360
x=70
Now that we found the missing angle, we have the find the value of x. 
We know that since it is a straight line, the two angels must add up to 180°
We can use the equation
70+x=180
x=110
Therefore the value of x is 110°
 
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Mr .Rowley has 16 homework papers and (2 exit tickets to return. Ms. Alvera has 64 homework papers and 60 exit
Kisachek [45]

The ratio of of number of homework papers to number of exit tickets of Mr Rowley and Ms. Alvera are not equivalent.

<h3>Ratio</h3>

A ratio is a number representing a comparison between two named things. It is also the relative magnitudes of two quantities usually expressed as a quotient.

Mr Rowley:

  • Homework papers = 16
  • Tickets to return = 2

Ratio of number of homework papers to number of exit tickets = 16 : 2

= 16 / 2

= 8 / 1

= 8 : 1

Ms Alvera:

  • Homework papers = 64
  • Tickets to return = 60

Ratio of number of homework papers to number of exit tickets = 64 : 60

= 64/60

= 16 / 15

= 16 : 15

Therefore, the ratio of of number of homework papers to number of exit tickets of Mr Rowley and Ms. Alvera are not equivalent.

Learn more about ratio:

brainly.com/question/2328454

#SPJ1

4 0
1 year ago
An advertising company designs a campaign to introduce a new product to a metropolitan area of population 3 Million people. Let
Advocard [28]

Answer:

P(t)=3,000,000-3,000,000e^{0.0138t}

Step-by-step explanation:

Since P(t) increases at a rate proportional to the number of people still unaware of the product, we have

P'(t)=K(3,000,000-P(t))

Since no one was aware of the product at the beginning of the campaign and 50% of the people were aware of the product after 50 days of advertising

<em>P(0) = 0 and P(50) = 1,500,000 </em>

We have and ordinary differential equation of first order that we can write

P'(t)+KP(t)= 3,000,000K

The <em>integrating factor </em>is

e^{Kt}

Multiplying both sides of the equation by the integrating factor

e^{Kt}P'(t)+e^{Kt}KP(t)= e^{Kt}3,000,000*K

Hence

(e^{Kt}P(t))'=3,000,000Ke^{Kt}

Integrating both sides

e^{Kt}P(t)=3,000,000K \int e^{Kt}dt +C

e^{Kt}P(t)=3,000,000K(\frac{e^{Kt}}{K})+C

P(t)=3,000,000+Ce^{-Kt}

But P(0) = 0, so C = -3,000,000

and P(50) = 1,500,000

so

e^{-50K}=\frac{1}{2}\Rightarrow K=-\frac{log(0.5)}{50}=0.0138

And the equation that models the number of people (in millions) who become aware of the product by time t is

P(t)=3,000,000-3,000,000e^{0.0138t}

5 0
3 years ago
Need Help!!! ASAP
RoseWind [281]

Answer:

P(green)+P(yellow)=\frac{3}{8}+\frac{1}{8}

P(green)+P(yellow)=\frac{1}{4}+\frac{1}{4}

P(green)+P(yellow)=\frac{3}{7}+\frac{1}{14}

Step-by-step explanation:

The given probabilities are:

P(red)=\frac{2}{7}

P(blue)=\frac{3}{14}

Their sum is P(red)+P(blue)=\frac{2}{7}+\frac{3}{14}

The probabilities that will complete the model should add up to \frac{1}{2} so that the sum of all probabilities is 1.

P(green)+P(yellow)=\frac{2}{7}+\frac{2}{7}\ne\frac{1}{2}

P(green)+P(yellow)=\frac{3}{8}+\frac{1}{8}=\frac{1}{2}

P(green)+P(yellow)=\frac{1}{4}+\frac{1}{4}=\frac{1}{2}

P(green)+P(yellow)=\frac{5}{21}+\frac{11}{21}\ne\frac{1}{2}

P(green)+P(yellow)=\frac{3}{7}+\frac{1}{14}=\frac{1}{2}

5 0
3 years ago
<img src="https://tex.z-dn.net/?f=%28x%20-%207%29%28x%20-%205%29" id="TexFormula1" title="(x - 7)(x - 5)" alt="(x - 7)(x - 5)" a
Rufina [12.5K]

\huge\textsf{Hey there!}

\large\textsf{(x - 7) (x - 5)}

\large\text{DISTRIBUTE each of the numbers}

\large\textsf{x(x) + (-5)x + (-7(x) + (-7)(-5)}

\large\textsf{x(x) =  \bf x}\bf ^2

\large\textsf{x(-5) = \bf -5x}

\large\textsf{-7(x) = \bf -7x}

\large\textsf{(-7)(-5) = \bf 35}

\mathsf{x^2 - 5x -7x + 35}

\large\text{COMBINE the LIKE TERMS}

\mathsf{x^2 -(5x - 7x) + 35}

\mathsf{-5x -7x = \bf -12x}

\mathsf{x^2 - 12x + 35}

\boxed{\huge\text{Answer: \bf x}^2 \huge\text{\bf - 12x + 35}}\huge\checkmark

\large\text{Good luck on  your assignment and enjoy your day!}

~\frak{Amphitirite1040:)}

3 0
3 years ago
Read 2 more answers
10(n^2+n) -6 (n^2 - 2). simplify the following
Setler [38]

Answer:

4n^2 + 22n

Step-by-step explanation:

10(n^2+n) -6 (n^2 - 2)

10n^2 + 10n - 6n^2 + 12

4n^2 + 22n

3 0
3 years ago
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