Answer:
a) (11/7, 9/7)
b) There's no point of intersection
Step-by-step explanation:
a) x - 2y + 1 = 0
2x + 3y - 7 = 0
To find the point of intersection, we need to solve the system of equations and the result will be the point of intersection (x,y)
Now we substitute x in the second equation:
Now we substitute y in our first equation.
.
The point of intersection is (11/7, 9/7)
b) x -2y +11 =0
-x + 2y - 13 =0
We are going to follow the same procedure:
Since this system of equations doesn't have a solution, the system has no point of intersection.
Answer:
see in pdf the solution is there.
Step-by-step explanation:
The picture is not clear. let me assume
y = (x^4)ln(x^3)
product rule :
d f(x)g(x) = f(x) dg(x) + g(x) df(x)
dy/dx = (x^4)d[ln(x^3)/dx] + d[(x^4)/dx] ln(x^3)
= (x^4)d[ln(x^3)/dx] + 4(x^3) ln(x^3)
look at d[ln(x^3)/dx]
d[ln(x^3)/dx]
= d[ln(x^3)/dx][d(x^3)/d(x^3)]
= d[ln(x^3)/d(x^3)][d(x^3)/dx]
= [1/(x^3)][3x^2] = 3/x
... chain rule (in detail)
end up with
dy/dx = (x^4)[3/x] + 4(x^3) ln(x^3)
= x^3[3 + 4ln(x^3)]
Answer:
30 s
Step-by-step explanation:
When the ball hits the ground h=0. To find the time t when this happens we must solve the equation h=0.
●h= 0
● -12t^2+360t =0
● t(-12t +360) = 0
● t = 0 or -12t +360 =0
● t=0 or -12t = -360
● t=0 or 12t =360
● t=0 or t=360/12
● t=0 or t= 30
The equation has two solutions.
The ball was fired with an initial speed of 800 feet per second so it cannot hit the ground at t=0.
So the ball hits the ground after 30 s.
