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lisabon 2012 [21]

4 years ago

8

5/8 as a fraction and a decimal

1 answer:

myrzilka [38]4 years ago

3 0

0.625 and 62.5%
here you go

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When Katya factored 288, she listed these factors: 1, 2, 3, 6, 8, 9, 12, 16, 18, 32, 36, 48, 72, 96, and 288. Use a factor rainb

REY [17]

Answer:

Please find a representation of the factor rainbow below.

The missing factors are: 4, 24, and 144

Step-by-step explanation:

The factors of a number are those numbers that can divide another number without remainder. In this case where Katya factored 288, it means she listed the numbers that can divide 288 without reminder (factors of 288). However, among the factors she listed, THREE factors are missing.

To get the missing factors, we can use a FACTOR RAINBOW, which is a display of the factors of a number in a rainbow shape. The factors are arranged from smallest to largest number in such a way that the two numbers attached to a line can be multiplied to give the original number.

From the attached factor rainbow (see attached image), it can be observed that factors: 4, 24, and 144 are missing in the list of factors Katya provided.

4 0

3 years ago

0.01 is blank times as much as 0.001 please answer i will brainliest

coldgirl [10]

Answer:

100

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Suppose that P(n) is a propositional function. Determine for which nonnegative integers n the statement P(n) must be true if a)

wel

Solution :

a). $P(0)$ is true

Then , $P(0+2)=P(2)$ is true.

$P(2+2)=P(4)$ is true

$P(4+2)=P(6)$ is true.

Therefore, we see that $P(n)$ is true for all the even integers : $\{0, 2,4,6,...\}$

b). $P(0)$ is true

Then , $P(0+3)=P(3)$ is true.

$P(3+3)=P(6)$ is true

$P(6+3)=P(9)$ is true.

Therefore, we see that $P(n)$ is true for all the multiples of 3 : $\{0, 3,6,9,12,...\}$

c). $P(0)$ and $P(1)$ is true, then $P(0+2)=P(2)$ is true

$P(1)$ and $P(2)$ is true, then $P(1+2)=P(3)$ is true.

$P(2)$ and $P(3)$ is true, then $P(2+2)=P(4)$ is true.

So, we observe that $P(n)$ is true for all the non- negative integers : $\{0, 1,2,3,4,5,6,...\}$ .

d). $P(0)$ is true,

So, $P(0+2)$ and $P(0+3)$ is true or $P(2)$ and $P(3)$ is true.

Now, $P(2)$ is true.

Again, $P(2+2)$ and $P(2+3)$ is true or $P(4)$ and $P(5)$ is true.

Now, $P(3)$ is true.

Again, $P(3+2)$ and $P(3+3)$ is true or $P(5)$ and $P(6)$ is true.

Thus,

$P(n)$ is true for all the non- negative integers except 1 : $\{0, 2,3,4,5,6,...\}$ .

3 0

3 years ago

Please answer correctly and no links pls

lutik1710 [3]

Answer: 13.) 49, 14.) 64

Step-by-step explanation:

7x7=49, 8x8=64

8 0

3 years ago

WILL GIVE BRAINLIEST IF YOUR RIGHT!!!!

Crazy boy [7]

Answer:

I.I

R.R

Step-by-step explanation:

R.R would be R.RRRR......

and I.I would be I.IIII...

5 0

3 years ago

Read 2 more answers