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2 years ago

REVIEW

Mathematics

1 answer:

sergejj [24]2 years ago

3 0

Answer:

a. The resulting product cannot be greater than-10. (False)

b. The resulting product must be greater than 0. (True)

c. The resulting product cannot be less than 10. (True)

Step-by-step explanation:

Explaining Statement (a):

The integer that is given is -10,

Let it will b multiplied with another negative integers let say (-1). Starting with the smallest one in order to clarify all statement.

So, if the resultant product is represented by x, So:

x = (-10)(-1)

Using the sign Multiplication rule which is {(-)*(-)} = +

x = 10

While looking at the result It is greater than -10 because 10 is greater than -10 (So, First Statement is False)\
Similarly, the resulting product is greater than 0 because 10 is greater than 0 (So, 2nd statement is true)
At the end, the minimum integer choose to multiply with the -10 will be -1. It neither be -0.5 because -0.5 is not an integer. Hence answer will never ever be less than 10. (Last statement is True)

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We conclude that young women are delaying marriage and marrying at a later age.

Step-by-step explanation:

We are given that the average age of brides marrying for the first time is 23.9 years with a population standard deviation of 4.2 years.

The sociologist randomly samples 100 marriage records and determines the average age of the first time brides is 24.9 years.

Let $\mu$ = average age of brides marrying for the first time.

So, Null Hypothesis, $H_0$ : $\mu$ = 23.9 years {means that young women are not delaying marriage and marrying at a later age}

Alternate Hypothesis, $H_A$ : $\mu$ > 23.9 years {means that young women are delaying marriage and marrying at a later age}

The test statistics that would be used here One-sample z test statistics as we know about the population standard deviation;

T.S. = $\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, $\bar X$ = sample average age of the first time brides = 24.9 years

$\sigma$ = population standard deviation = 4.2 years

n = sample of marriage records = 100

So, the test statistics = $\frac{24.9-23.9}{\frac{4.2}{\sqrt{100} } }$

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The value of z test statistics is 2.381.

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Since our test statistic is more than the critical value of z as 2.381 > 2.326, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which we reject our null hypothesis.

Therefore, we conclude that young women are delaying marriage and marrying at a later age.

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