Answer:
Step-by-step explanation:
just times everything 3.5 as 42/12=3.5
490g margarine
420g sugar
350ml syrup
840g oats
175g raisins
The evaluation of the expression is S equals zero
<h3>Answer: Choice C</h3>
RootIndex 12 StartRoot 8 EndRoot Superscript x
12th root of 8^x = (12th root of 8)^x
![\sqrt[12]{8^{x}} = \left(\sqrt[12]{8}\right)^{x}](https://tex.z-dn.net/?f=%5Csqrt%5B12%5D%7B8%5E%7Bx%7D%7D%20%3D%20%5Cleft%28%5Csqrt%5B12%5D%7B8%7D%5Cright%29%5E%7Bx%7D)
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Explanation:
The general rule is
![\sqrt[n]{x} = x^{1/n}](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5D%7Bx%7D%20%3D%20x%5E%7B1%2Fn%7D)
so any nth root is the same as having a fractional exponent 1/n.
Using that rule we can say the cube root of 8 is equivalent to 8^(1/3)
![\sqrt[3]{8} = 8^{1/3}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B8%7D%20%3D%208%5E%7B1%2F3%7D)
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Raising this to the power of (1/4)x will have us multiply the exponents of 1/3 and (1/4)x like so
(1/3)*(1/4)x = (1/12)x
In other words,


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From here, we rewrite the fractional exponent 1/12 as a 12th root. which leads us to this
![8^{(1/12)x} = \sqrt[12]{8^{x}}](https://tex.z-dn.net/?f=8%5E%7B%281%2F12%29x%7D%20%3D%20%5Csqrt%5B12%5D%7B8%5E%7Bx%7D%7D%20)
![8^{(1/12)x} = \left(\sqrt[12]{8}\right)^{x}](https://tex.z-dn.net/?f=8%5E%7B%281%2F12%29x%7D%20%3D%20%5Cleft%28%5Csqrt%5B12%5D%7B8%7D%5Cright%29%5E%7Bx%7D%20)
Answer:
- so 8 cubed (8 × 8 × 8) in standard form is: 512
- so 8 cubed (8 × 8 × 8) in exponential form is: 8³
Step-by-step explanation:
As we know that
The cube of any given number is that number times itself.
For example, 8 cubed, denoted by 8³ is equal to 8 × 8 × 8.
An exponent basically indicates the number of times we must multiply the base number. For example, to compute 8³, we multiply 3 three times (8×8×8).
- so 8 cubed (8 × 8 × 8) in standard form is: 512
- so 8 cubed (8 × 8 × 8) in exponential form is: 8³
Answer:
B
Step-by-step explanation:
Y is the starting point so it would be y=12322 and it becomes 1.18 because you add 100 to 18