Answer:
<em><u>1- The graph provides a comparison of the different marketing strategies</u></em>
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<u><em>2- The graph helps in selecting the best marketing strategy to improve sales</em></u>
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Explanation:
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Answer:
Electro negativity decreases down the group
Explanation:
One of the known periodic trends is that electro negativity decreases down the group but increases across the period. The electro negativity of fluorine is 3.98 on the Pauling's scale while that of bromine is 2.96. Hence the magnitude of charge separation and degree of partial positive charge on hydrogen in HF must be much greater than that of HBr to a large extent due to the significant difference in electronegativity in HF compared to HBr.
Complete Question
The complete question is shown on the first uploaded image
Answer:
The value is 
Explanation:
From the question we are told that
The voltage of the cell is 
Generally 
is mathematically represented as
Where 
is the equilibrium constant for this auto-ionization of water with a value 
Generally the 
is mathematically represented as
=> 
=> 
This is mathematically represented as
Where n is the number of moles which in this question is n = 1
So
=> 
So
=> 
=>
<span>We can solve this problem by assuming that the decay of
cyclopropane follows a 1st order rate of reaction. So that the
equation for decay follows the expression:</span>
A = Ao e^(- k t)
Where,
A = amount remaining at
time t = unknown (what to solve for) <span>
Ao = amount at time zero = 0.00560
M </span><span>
<span>k = rate constant
t = time = 1.50 hours or 5400 s </span></span>
The rate constant should
be given in the problem which I think you forgot to include. For the sake of
calculation, I will assume a rate constant which I found in other sources:
k = 5.29× 10^–4 s–1 (plug in the correct k value)
<span>Plugging in the values
in the 1st equation:</span>
A = 0.00560 M * e^(-5.29 × 10^–4 s–1 * 5400 s )
A = 3.218 <span>× 10^–4 M (simplify
as necessary)</span>
