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Amanda [17]
4 years ago
5

What is the molecular formula for a compound with an empirical formula of CH2O if its experimentally determined molecular weight

is 180 amu?
Chemistry
1 answer:
NNADVOKAT [17]4 years ago
3 0

Answer:

C6H12O6.

Explanation:

Adding up the relative atomic masses of the elements

C + 2H + O

= 12 + 2*1 + 16.

= 30.

180 / 30 = 6  so the molecular formula is:

C6H12O6.

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Which of the following is the electrical charge on an atom that contains 6 electrons, 3 neutrons, and 4 protons?
Y_Kistochka [10]

Answer:

Its electrical charge is -2.

4 0
3 years ago
Veronica is taking an average of 16 height measurements in a brand-new experiment. Which term is this the best example of? repli
Karolina [17]

Answer:

repetition

Explanation:

Taking an average of 16 height measurements is an example of repetition. Repetition involves making and taking repeated measurements in an experiment.

The goal is to achieve a highly accurate and precise data from the experiment.

  • Replication involves duplicating another experiment and testing to see how valid they are.
  • Since Veronica's experiment is a brand new one, it's hypothesis has not been tested or replicated in any way.
  • Therefore, it is not a replication.
  • But she is repeating the experiment to obtain different values.
3 0
4 years ago
Read 2 more answers
Un anillo, de masa 90 gramos, contiene 59,1% de oro. ¿Cuál es el valor del anillo si cada mol de oro vale S/.1800?. Considere el
LekaFEV [45]

Answer:

S/.486 es el valor del anillo

Explanation:

Para hallar el precio del anillo se deben encontrar las moles de oro que contiene este.

Si el anillo es de 90g y solo el 59.1% contiene oro, la cantidad de oro en gramos es:

90g × 59.1% = 53.19g Oro en el anillo

Ahora, para convertir los gramos de oro a moles se debe usar la masa atómica del oro (197g/mol), así:

53.19g × (1mol / 197g) = <em><u>0.27 moles de oro contiene el anillo</u></em>.

Ya que cada mol de oro cuesta S/.1800, 0.27 moles de oro (Y por lo tanto, el anillo) costarán:

0.27mol × (S/.1800 / 1mol oro) =

<h3>S/.486 es el valor del anillo</h3>
8 0
3 years ago
Please help i will give brainliest
ExtremeBDS [4]
Question 2 answer is A
7 0
3 years ago
A chemistry teacher is able to grade chemistry labs at a rate of 5 labs for every 3 minutes. They need to grade 165 labs how man
PIT_PIT [208]

Answer:

1.65hr

Explanation:

Given parameters:

Number of labs  = 5 labs

 Time taken  = 3 minutes

Unknown:

Time taken in hours to grade 165 labs  = ?

Solution:

Let us find the rate of the teacher;

  Rate  = \frac{number of labs}{time}  

  Insert the parameters and solve;

   Rate  = \frac{5}{3}   = 1.67labs/min

Now;

   Time to grade 165 labs  = \frac{number of labs}{rate}  

   Time to grade 165 labs  = \frac{165}{1.67}   = 98.8min

  Since;

               60min = 1hr

               98.8min  = \frac{98.8}{60}   = 1.65hr

3 0
3 years ago
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