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Amanda [17]
3 years ago
5

What is the molecular formula for a compound with an empirical formula of CH2O if its experimentally determined molecular weight

is 180 amu?
Chemistry
1 answer:
NNADVOKAT [17]3 years ago
3 0

Answer:

C6H12O6.

Explanation:

Adding up the relative atomic masses of the elements

C + 2H + O

= 12 + 2*1 + 16.

= 30.

180 / 30 = 6  so the molecular formula is:

C6H12O6.

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A compound contains sulfur, oxygen, and chlorine. Analysis shows that it contains by mass 26.95% sulfur and 59.61% chlorine. Wha
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Answer:

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In order to know the empirical formula, we have to follow a series of steps.

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Consider the following intermediate reactions.
Alja [10]

2.1648 kg of CH4 will generate 119341 KJ of energy.

Explanation:

Write down the values given in the question

CH4(g) +2 O2 → CO2(g) +2 H20 (g)

ΔH1 = - 802 kJ

2 H2O(g)→2 H2O(I)

ΔH2= -88 kJ

The overall chemical reaction is

CH4 (g)+2 O2(g)→CO2(g)+2 H2O (I) ΔH2= -890 kJ

CH4 +2 O2 → CO2 +2 H20

(1mol)+(2mol)→(1mol+2mol)

Methane (CH4) = 16 gm/mol

oxygen (O2) =32 gm/mol

Here 1 mol CH4 ang 2mol of O2 gives 1mol of CO2 and 2 mol of 2 H2O

which generate 882 KJ /mol

Therefore to produce 119341 KJ of energy

119341/882 = 135.3 mol

to produce 119341 KJ of energy, 135.3 mol of CH4 and 270.6 mol of O2 will require

=135.3 *16

=2164.8 gm

=2.1648 kg of CH4

2.1648 kg of CH4 will generate 119341 KJ of energy

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