Graph the inequalities to find the vertices of the shaded region: (2, 3) and (8, 0).
Now, evaluate the the function C = x + 3y at those vertices to find the minimum value.
C = x + 3y at (2, 3) ⇒ C = (2) + 3(3) ⇒ C = 2 + 9 ⇒ C = 11
C = x + 3y at (8, 0) ⇒ C = (8) + 3(0) ⇒ C = 8 + 0 ⇒ C = 8
The minimum value occurs at (8, 0) with a minimum of C = 8
Answer: A
Answer:
<u>Option C. (0,-5)</u>
Step-by-step explanation:
See the attached figure.
As shown the shaded area represents the solution of the given inequality:
y < 6x - 4
The given options are the points:
A. (0,3) B.(0,11) C. (0,-5) D.(0,4)
Comparing the given points to the graph.
So, the point that will lie at the shaded area represent solution to the linear inequality.
So, point (0,-5) is a solution to the linear inequality.
The answer is <u>option C. (0,-5)</u>
Note: the line y = 6x-4 is graphed using the table on the graph.
Answer:
HCF of 120 and 180 is 60 and hence a measuring tin of 60 litre volume should be bought.
If i understand the machine correctly and -3 is x and 8 is the final answer, f(x)=x+11
Found this when I was doing my own work, hope this helps.