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natka813 [3]
3 years ago
12

Joes Ice cream palace offers 3 different cones, 7 different toppings and 12 different flavors of ice cream. How many ice cream c

one combinations can be ordered?
Mathematics
1 answer:
Ostrovityanka [42]3 years ago
3 0

The solution would be like this for this specific problem:


Given:

3 different cones

7 different toppings

12 different flavors of ice cream

 

3 different cones * 7 different toppings * 12 different flavors of ice cream = 252 ice cream cone combinations 

So, 252 ice cream cone combinations can be ordered in Joes Ice Cream Palace.

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zaharov [31]

Answer:

x = 30° and 330°

Step-by-step explanation:

Assuming the intervals is {0 , 2π} or {0° , 360°}

tan\ x=\frac{-\sqrt{3} }{3} \\\\x=tan^{-1} (\frac{-\sqrt{3} }{3})\\\\x = -30

So it means it lies in the 2nd and 4th quadrant because tangent is negative in the 2nd and 4th quadrant

so the two solutions are

x = 30° and 330° or

x=\frac{\pi }{6}\ radians\ \ , \ \ \frac{11\pi }{6}\ radians

4 0
3 years ago
Find the distance between points P(6, 5) and Q(2, 4) to the nearest tenth.
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Answer:

√10

Step-by-step explanation:

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2 years ago
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Oxana [17]

y + 6 = 4/3(x - 2)

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y + 6 = 4/3x - 8/3

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-26/3 is the y-intercept so start the graph at coordinate (0, -26/3)

After you plot the y-intercept, add 4 to they y-coordinate and 3 to the x-coordinate of the y-intercept to get the next point.

0 + 3 = 3

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The next point should be at (3, -14/3)

Add as many points as your professor requires.

8 0
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Marysya12 [62]
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