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2 years ago

ANSWER FAST PLEASE what is the degree of the polynomial

Mathematics

1 answer:

STatiana [176]2 years ago

3 0

Answer:

The degree of a polynomial is the largest exponent on one of its variables (for a single variable), or the largest sum of exponents on variables in a single term (for multiple variables).

Step-by-step explanation:

ere, the term with the largest exponent is , so the degree of the whole polynomial is 6.

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A square has an area of 4 square centimeters. What is the length of one side, in centimeters?

Lunna [17]

Answer:

2 cm

Step-by-step explanation:

$\sqrt{4 cm^{2}} =2 cm$

7 0

2 years ago

Polygon ABCD is defined by the points A(-4,2) B(-2, 4), C(1, 3) & D(2,2). Match the coordinates of the points of the transfo

dalvyx [7]

Answer:

D'(-2, 2); C''(3, -1); A'''(4, -2); and B''(4, 2)

Step-by-step explanation:

See attachment for the figure.

For D', rotating the point (2, 2) 90° counterclockwise. This maps each point (x, y)→(-y, x); it takes (2, 2)→(-2, 2).

For C'', rotating the point (1, 3) 90° clockwise. This maps each point (x, y)→(y, -x); it takes (1, 3)→(3, -1).

For A''', rotating the point (-4, 2) 180° clockwise. This maps every point (x, y)→(-x, -y); it takes (-4, 2)→(4, -2).

For B'', rotating the point (-2, 4) 270° counterclockwise. This is the similar as rotating the point 90° clockwise. This maps every point (x, y)→(y, -x); it takes (-2, 4)→(4, 2).

8 0

3 years ago

-13x=90-2y -6x=48-2y

Kisachek [45]

While it's pretty obvious to most of us that

-13x=90-2y

-6x=48-2y

is a system of linear equations, it'd be well to include that info plus the instructions "solve this system of linear equations."

Subtract the 2nd equation from the first:

-13x=90-2y

+6x=-48+2y

-----------------------

-7x = 42. Then x = -42/7, or x = 6.

Now subst. 6 for x in either one of the given equations. Suppose we use the 2nd equation:

-6x=48-2y

Then -6(6)=48-2y, or -36 = 48 - 2y, or 2y = 48+ 36 = 84. Then y = 42.

The solution is (6, 42).

3 0

2 years ago

Determine the holes, vertical asymptotes, and horizontal asymptotes of the rational function y=3x^2+10x-8/x^2+7x+12

kompoz [17]

There would be a hole when x = -4.

If you factor both the top and the bottom, you will see that the factor (x + 4) is in both the numerator and denominator. Therefore, the would be a hole when x = -4 because that would also make the denominator 0.

8 0

3 years ago

Help me guys thx so much

navik [9.2K]

Answer:

Option D, $10x^4\sqrt{6} +x^3\sqrt{30x} -10x^4\sqrt{3} -x^3\sqrt{15x}$

Step-by-step explanation:

Step 1: Multiply

$(\sqrt{10x^4} -x\sqrt{5x^2} )*(2\sqrt{15x^4} + \sqrt{3x^3})\\ (\sqrt{10 * x^2 * x^2} -x\sqrt{5 * x^2} ) * (2\sqrt{15 * x^2 * x^2} +\sqrt{3 * x^2 * x})\\(x^2\sqrt{10} -x^2\sqrt{5} )*(2x^2\sqrt{15} +x\sqrt{3x}) \\\\$

$(x^2\sqrt{10}*2x^2\sqrt{15} )+(x^2\sqrt{10}*x\sqrt{3x} ) + (-x^2\sqrt{5} *2x^2\sqrt{15}) + (-x^2\sqrt{5} *x\sqrt{3x}$

$(2x^4\sqrt{150} ) + (x^3\sqrt{30x}) + (-2x^4\sqrt{75}) + (-x^3\sqrt{15x} )$

$2x^4\sqrt{5^2*6} + x^3\sqrt{30x} -2x^4\sqrt{5^2*3} -x^3\sqrt{15x}$

$10x^4\sqrt{6} +x^3\sqrt{30x} -10x^4\sqrt{3} -x^3\sqrt{15x}$

Answer: Option D, $10x^4\sqrt{6} +x^3\sqrt{30x} -10x^4\sqrt{3} -x^3\sqrt{15x}$

6 0

3 years ago

Read 2 more answers