Ask question

Ask question

All categories

3 years ago

14

Linda had 45 fliers to post around town. She posted 1/3 of them. This week she posted 2/3 of the remaining fliers. How many flie

rs has she not posted?

1 answer:

garik1379 [7]3 years ago

4 0

She has not posted 10 fliers.

You might be interested in

M= -(4+m)+2<br> solve for m

Allisa [31]

Answer:

m = -1

Step-by-step explanation:

m = - (4 + m) + 2

m = -4 - m + 2

m = -2 - m

+m +m

2m = -2

/2 /2

m = -1

Hope this helps!

8 0

3 years ago

Read 2 more answers

What is the average rate of change

algol [13]

The average rate of change between two input values is the total change of the function values (output values) divided by the change in the input values.

6 0

3 years ago

Find the midsegment of triangle ABC so that it is parallel to side BC and label it as segment EG on the graph coordinate of E: _

Sholpan [36]

Answer:

Coordinate of E: (-2,3) Coordinate of G: (2.5, 1.5)

Step-by-step explanation:

You first have to find the midpoints of AC and AB.

AC X coordinate:

X1+X2/2

Substitute the x points of AC in

1+(-5)/2=-2

AC Y coordinate:

Y1+Y2/2=3

Substitute the y points of AC in

5+1/2=3

You do the same thing with the AB line. I am pretty sure this works and I hope this helps!

5 0

3 years ago

Can someone plz help plz show work

aliya0001 [1]

Answer:

<h2>LA = 24 ft²</h2>

Step-by-step explanation:

In the base we have the right triangle. Use the Pythagorean theorem for to calculate the hypotenuse:

$h^2=4^2+3^2\\\\h^2=16+9\\\\h^=25\to h=\sqrt{25}\\\\h=5\ ft$

The Lateral Area is the sum of the areas of three rectangles:

$4\ ft\ \times\ 2\ ft\to A_1=(4)(2)=8\ ft^2\\\\3\ ft\ \times\ 2\ ft\to A_2=(3)(2)=6\ ft^2\\\\5\ ft\ \times\ 2\ \ft\to A_3=(5)(2)=10\ ft^2$

The Lateral Area:

$LA=A_1+A_2+A_3\to LA=8+6+10=24\ ft^2$

8 0

3 years ago

Algebra 2 (picture shown)

TEA [102]

Answer:

<em>M(13)=14.3 gram</em>

Step-by-step explanation:

<u>Exponential Decay Function</u>

The exponential function is used to model natural decaying processes, where the change is proportional to the actual quantity.

An exponential decaying function is expressed as:

$C(t)=C_o\cdot(1-r)^t$

Where:

C(t) is the actual value of the function at time t

Co is the initial value of C at t=0

r is the decaying rate, expressed in decimal

The element has an initial mass of Mo=970 grams, the decaying rate is r=27.7% = 0.277 per minute.

The equation of the model is:

$M(t)=M_o\cdot(1-r)^t$

$M(t)=970\cdot(1-0.277)^t$

Operating:

$M(t)=970\cdot 0.723^t$

After t=13 minutes the remaining mass is:

$M(13)=970\cdot 0.723^{13}$

Calculating:

M(13)=14.3 gram

4 0

3 years ago