Answer:
The answer is that adult tickets cost $44.50 and child tickets cost $19.
Step-by-step explanation:
Let c = the cost of child tickets and a = the cost of adult tickets.
The total amount is equal to the number of adult tickets time the cost of adult tickets plus the number of child tickets times the cost of child tickets. Set up two equations:
2a + 4c = 165
4a + 3c = 235
Solve the top equation for a:
2a + 4c = 165
2a = 165 - 4c
a = 165/2 - 4c/2
a = 82.5 - 2c
Substitute into the second equation:
4a + 3c = 235
4(82.5 - 2c) + 3c = 235
330 - 8c + 3c = 235
-5c = -95
c = -95 / -5 = 19, so child ticket cost $19.
Solve for a:
a = 82.50 - 2c
a = 82.50 - 2(19)
a = 82.50 - 38
a = $44.50, so adult tickets cost $44.50.
Proof using the first equation for the Johnson family:
2a + 4c = 165
2(44.50) + 4(19) = 165
89 + 76 = 165
165 = 165
Proof using the second equation for the Robison family:
4a + 3c = 235
4(44.50) + 3(19) = 235
178 + 57 = 235
235 = 235
Step-by-step explanation:
The answer is mentioned above.
Answer:
D) 2
Step-by-step explanation:
Use the following slope formula:
<em>m </em>(slope) = (y₂ - y₁)/(x₂ - x₁)
Let:
(x₁ , y₁) = (4 , 1)
(x₂ , y₂) = (1 , -5)
Plug in the corresponding numbers to the corresponding variables:
<em>m</em> = (-5 - 1)/(1 - 4)
Simplify. Remember to follow PEMDAS. First subtract, then divide:
<em>m</em> = (-5 - 1)/(1 - 4)
<em>m</em> = (-6)/(-3)
<em>m</em> = 2
D) 2 is your answer.
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Answer:
c
Step-by-step explanation:
the -2 causes a shift 2 units right
