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Arada [10]
3 years ago
8

If cscx=3, 90 degrees

Mathematics
1 answer:
ludmilkaskok [199]3 years ago
4 0
We are given with 90<x<180 degrees and asks for the value of sin(x/2), cos(x/2) and tan(x/2). We just substitute the maximum and minimum angle to the equations. sin (180/2) is equal to 1 and sin (90/2) is equal to \frac{ \sqrt{2} }{2} to 1. cos (x/2) is equal to 0≤y≤<span>\frac{ \sqrt{2} }{2}. tan (x/2) is equal to 1 to infinity. </span>
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Find the distance between the points (1, 4) and (-5, -4) on the coordinate plane. Show your work to justify your answer!
Katyanochek1 [597]

The distance is 8 you just have to measure off of the y axis

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3 years ago
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A competition problem requires one hour to fully develop (write, proofread, edit, and typeset). This problem is then given to 30
Vsevolod [243]

Answer:

1250

Step-by-step explanation:

30,000/24

divide both sides by 24 to get 1250.

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2 years ago
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A sample of 81 account balances of a credit company showed an average balance of $1,200 with a standard deviation of $126.
TEA [102]

Answer:

(a) Null Hypothesis, H_0 : \mu = $1,150  

    Alternate Hypothesis, H_A : \mu \neq $1,150

(b) The test statistic is 3.571.

(c) We conclude that the mean of all account balances is significantly different from $1,150.

Step-by-step explanation:

We are given that a sample of 81 account balances of a credit company showed an average balance of $1,200 with a standard deviation of $126.

We have test the hypothesis to determine whether the mean of all account balances is significantly different from $1,150.

<u><em>Let </em></u>\mu<u><em> = mean of all account balances</em></u>

(a)So, Null Hypothesis, H_0 : \mu = $1,150     {means that the mean of all account balances is equal to $1,150}

Alternate Hypothesis, H_A : \mu \neq $1,150    {means that the mean of all account balances is significantly different from $1,150}

The test statistics that will be used here is <u>One-sample t test statistics</u> as we don't know about population standard deviation;

                               T.S.  = \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }  ~ t_n_-_1

where, \bar X = sample average balance = $1,200

             s = sample standard deviation = $126

             n = sample of account balances = 81

(b) So, <u>test statistics</u>  =  \frac{1,200-1,150}{\frac{126}{\sqrt{81} } }  ~ t_8_0

                               =  3.571

The value of the sample test statistics is 3.571.

(c) <u>Now, P-value of the test statistics is given by the following formula;</u>

          P-value = P( t_8_0 > 3.571) = <u>Less than 0.05%</u>

Because in the t table the highest critical value for t at 80 degree of freedom is given between 3.460 and 3.373 at 0.05% level.

Now, since P-value is less than the level of significance as 5% > 0.05%, so we sufficient evidence to reject our null hypothesis.

Therefore, we conclude that the mean of all account balances is significantly different from $1,150.

8 0
3 years ago
PLEASE HELP FOR BRAINLIEST ANSWER NEED TO KNOW IF IM CORRECT
Juliette [100K]
You're wrong its letter a

3 0
2 years ago
18 bottles of water cost $9. How much does it cost for one bottle of water? How much bottles can you buy with $6?​
Musya8 [376]

Answer:

Water cost 2$ you can buy 3 water bottles with 6$

Step-by-step

I did myself

5 0
3 years ago
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