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JulsSmile [24]
4 years ago
9

Predict the change in a runner’s finishing time with a wind speed of 5meters/second.

Mathematics
2 answers:
Karolina [17]4 years ago
4 0

Answer:

t = -1.24

Step-by-step explanation:

From the equation;

t = 0.0119s² - 0.308 s -0.0003

Where t is the change in a runner's performance, and s is the tail wind speed.

But s = 5 m/s

Therefore;

t = 0.0119 (5²) - 0.308(5) -0.0003

 = 0.2975 - 1.54 - 0.0003

 = - 1.2428

Since, negative means a runner finishes with a lower time, then;

t = -1.2428 to the nearest hundredth

  = -1.24

zubka84 [21]4 years ago
4 0

Answer:

<em>The change t was -1.243 seconds</em>

Step-by-step explanation:

We already have the equation that models the change in the runner's time based on the wind speed s.

This relation between t and s is given by a quadratic function.

If the function is:

t = 0.0119s ^ 2 -0.308s -0.0003

To predict the change in the completion time when the speed is 5m/s, we must replace s = 5 in the equation.

Then we substitute s = 5

t = 0.0119(5) ^ 2 -0.308(5) -0.0003\\\\t = -1,243 s

<em>The change was -1.243 seconds</em>

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Answer: The translation rule that maps point D ( 7 , − 3 ) onto point D ' ( 2 , 5 )

is (x , y) → (x - 5 , y + 8)

Step-by-step explanation:

Let us revise the translation

If the point (x , y) translated horizontally to the right by h units  then its image is (x + h , y)

If the point (x , y) translated horizontally to the left by h units  then its image is (x - h , y)

If the point (x , y) translated vertically up by k units  then its image is (x , y + k)

If the point (x , y) translated vertically down by k units  then its image is (x , y - k)

(x , y) → (x ± h , y ± k) the right arrow symbol used to show the

translation from a point to its image

Example:

∵ P (0 , 0) → P' (1 , 2)

∴ The rule is (x , y) → (x + 1 , y + 2)

Let us find the translation rule that maps point D ( 7 , − 3 ) onto

point D' (2 , 5)

∵ Point (x , y) = (7 , -3)

∵ Its image after translation (x + h , y + k) = (2 , 5)

∴ x + h = 2

∵ x = 7

∴ 7 + h = 2

- Subtract 7 from both sides

∴ h = -5

∵ y + k = 5

∵ y = -3

∴ -3 + k = 5

- Add 3 to both sides

∴ k = 8

∴ The rule of translation is (x , y) → (x - 5 , y + 8)

The translation rule that maps point D ( 7 , − 3 ) onto point D ' ( 2 , 5 )

is (x , y) → (x - 5 , y + 8)

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