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posledela
3 years ago
7

In the early 1970's, Canada Post started using six-character postal codes. Each postal code uses three letters and three digits

in an alternating pattern. How many different Canadian postal codes are possible?
Mathematics
1 answer:
pogonyaev3 years ago
4 0
A Canadian postal code looks  like this:

                   K1A 3B1 .

So you have:  letter - digit - letter - digit - letter - digit .

The question doesn't say anything about restrictions on
which letters can be used, or restrictions on repeating letters
or digits within one postal code. So as far as we know, each
letter can be any one of 26, and each digit can be any one of 10.

The total number of possibilities would be

                 (26·10·26)  ·  (10·26·10)  =  17,576,000 .

In the real world, though, (or at least in Canada), Postal codes
don't include the letters D, F, I, O, Q or U, and the first letter
does not use W or Z. When you work it out with these restrictions,
it means there's a theoretical limit of 7.2 million postal codes.
The practical limit is a bit lower, as Canada Post reserves some
codes for special functions, such as for test or promotional purposes. 
One example is the code H0H 0H0 for Santa Claus !  Other special
codes are for sorting mail bound for destinations outside Canada.

At the present time, there are a little over 830,000 active postal codes.
That's about 12% of the total possibilities, so there are still plenty of codes
left for expansion.
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<u>Value of f(x) when x = 0:</u>

Substituting x = 0 in the function f(x)=x^{3}-6 x^{2}+4 x+7, we have;

f(0)=(0)^{3}-6 (0)^{2}+4 (0)+7

f(0)=0-0+0+7

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Thus, the value of f(0) is 7.

<u>Value of f(x) when x = 5:</u>

Substituting x = 5 in the function f(x)=x^{3}-6 x^{2}+4 x+7, we have;

f(5)=(5)^{3}-6 (5)^{2}+4 (5)+7

f(5)=125-150+20+7

f(5)=2

Thus, the value of f(5) is 2.

<u>Average rate of change:</u>

The average rate of change can be determined using the formula,

Rate \ of \ change=\frac{f(b)-f(a)}{b-a}

where a=0 and b=5

Thus, we have;

Rate \ of \ change=\frac{f(5)-f(0)}{5-0}

Rate \ of \ change=\frac{2-7}{5-0}

Rate \ of \ change=\frac{-5}{5}

Rate \ of \ change=-1

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3 years ago
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