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Karo-lina-s [1.5K]
3 years ago
8

What is the equation of a vertical line passing through the point (−4, 7)? y = 7 y = −4 x = 7 x = −4

Mathematics
2 answers:
Katen [24]3 years ago
8 0
The equation of the vertical line passing through point -4,7 would be X = -4.
BartSMP [9]3 years ago
5 0

Answer:  The correct option is

(D) x=-4.

Step-by-step explanation:  We are given to find the equation of a vertical line passing through the point (-4, 7).

We now that

a vertical line is always parallel to the y-axis and is of the form

x=k~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)

Since the given vertical line passes through the point (-4, 7) so from equation (i), we have

-4=k\\\\\Rightarrow k=-4.

Substituting the value of k in equation (i), we get

x=-4.

Thus, the required equation of the line is x=-4.

Option (D) is CORRECT.

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Answer: this is the order from top to bottom.

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Step-by-step explanation:

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3 years ago
If 1/√a-√b=1/3 and 1/√a+√b=1/2, then find the difference of a and b.​
kow [346]

<u>ANSWER:</u>

If \frac{1}{\sqrt{a}-\sqrt{b}}=\frac{1}{3} and \frac{1}{\sqrt{a}+\sqrt{b}}=\frac{1}{2} then the difference of a and b is 6

<u>SOLUTION:</u>

Given, \frac{1}{\sqrt{a}-\sqrt{b}}=\frac{1}{3} →\sqrt{a}-\sqrt{b}=3 ----- (1)

And \frac{1}{\sqrt{a}+\sqrt{b}}=\frac{1}{2} → \sqrt{a}+\sqrt{b}=2 --- (2)

We have to find difference of a and b.

Now, add (1) and (2)

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\sqrt{a}+\sqrt{b}=2

Adding above two equations, we get,

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\begin{array}{l}{2 \sqrt{a}=5} \\\\ {\sqrt{a}=\frac{5}{2}} \\\\ {a=\frac{25}{4}}\end{array}

substitute \sqrt{a} value in (2)

\begin{array}{l}{\frac{5}{2}+\sqrt{b}=2} \\\\ {\sqrt{b}=\frac{2}{\sin \frac{5}{2}}} \\\\ {\sqrt{b}=\frac{4-5}{2}} \\\\ {\sqrt{b}=\frac{-1}{2}} \\\\ {b=\frac{1}{4}}\end{array}

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Hence, the difference of a and b is 6.

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4 years ago
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