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barxatty [35]
3 years ago
14

True or False. A sinusoid is a function whose values repeat based on positions of a point that moves around a circle.

Mathematics
2 answers:
Gre4nikov [31]3 years ago
3 0

The <em>correct answer</em> is:

True.

Explanation:

A sinusoidal function is based on the sine function, or sine wave.

The sine wave repeats based on its <em>period</em>. The period of the sine function is 2π, or 360°. Depending on the transformations applied to the function, the period of the transformed function may be different, but will always be based around this idea of repeating every 2π radians.

Since 2π = 360°, this corresponds with a circle. This means the graph repeats based on positions of a point that move around a circle.

Digiron [165]3 years ago
3 0

Answer:

true, like the other guy said

Step-by-step explanation:

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Write a number in each blank to complete each equation so that it has the requested number of solutions. a. Equation with no sol
Setler79 [48]

Answer:

The answer is  8x - 3x + 2 -x =<u> 4 </u>x + <u>2 </u> .

Step-by-step explanation:

Given:

8x - 3x + 2 -x = __ x + __

Now, to write a number in each blank to complete each equation so that it has the requested number of solutions.

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8x-3x+2-x

So, we add  the variables:

5x+2-x

And, then subtract it:

4x-2.

Thus, it remains:

4x-2.

So the complete equation is:

8x - 3x + 2 -x =<u> 4 </u>x + <u>2 </u>

Therefore, the answer is  8x - 3x + 2 -x =<u> 4 </u>x + <u>2 </u> .

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3 years ago
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Zolol [24]

Answer:

2) Yes

3) No

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5 0
2 years ago
Use any method to multiply (-14ab)(a + 3b - 4c).
NeX [460]

Answer:

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Step-by-step explanation:

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8 0
3 years ago
Write a coordinate proof to prove that the segment that joins the vertex angle of an isosceles triangle to the midpoint of its b
Natalija [7]

Answer:

Slope of the base segment line is zero, hence base segment is horizontal

Slope of the segment that joins the vertex angle to the midpoint of its base is undefined hence the line is vertical

Therefore, angle between base segment line and the segment line from the vertex angle to the midpoint is perpendicular

Therefore, the segment that joins the vertex angle to an isosceles triangle to the midpoint of its base is perpendicular to the base

Step-by-step explanation:

Here we prove the required relation as follows;

Let the isosceles be ABC

The coordinates of the points are

C = (0, 0) (Vertex)

A =  (-a, b)

C = (a, b)

P = (0, b) (Midpoint of base)

Therefore, the gradient or slope of the base AC is presented as follows;

Slope, m \, of \. base, \, AC= \frac{dy}{dx}  = \frac{b - b}{a - (-a)}  = \frac{0}{2\cdot a} = 0

Hence, segment AC is vertical

Slope, m \, of \, segment \ CP \,  joining \, vertex, \, to \, midpoint, P, on  \,AC = \frac{0 - b}{0 - 0}  = \frac{-b}{0} = Undifined.

Hence, segment CP is vertical

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3 years ago
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REY [17]
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