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4vir4ik [10]
2 years ago
6

bag contains 15 marbles numbered from 1 to 15. Two marbles are selected from the bag at the same time. Let event E = the two num

bers do NOT differ by 10 How many outcomes are in the complement of E? A) 5 B) 10 C) 25 D) 200
Mathematics
2 answers:
lbvjy [14]2 years ago
7 0
The numbers DO differ by 10 if they are

- 1 and 11
- 2 and 12
- 3 and 13
- 4 and 14
- 5 and 15

Each outcome technically has two ways of occurring, but since we're taking two marbles at a time, that would be the same as saying, for instance, that drawing 1 and 11 is the same as drawing 11 and 1. We only count such an event once.

So the answer is (a) 5.
Kisachek [45]2 years ago
6 0

Answer:

5!

Step-by-step explanation:

The complement of E is when the numbers differ by 10,

(1, 11), (2, 12), (3, 13), (4, 14), (5, 15)

Thus, there are 5 outcomes where the numbers differ by 10.

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part 1 : explaining how to get the coordinates of B

part 2 : the gradient of BD

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3 years ago
Write an equation for a line perpendicular to y= -4x +2 and passing through the point (12,6)
gtnhenbr [62]

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y=\frac{1}{4} x+3

Step-by-step explanation:

5 0
2 years ago
Max makes and sells posters. The function p(x)= -10x^2 +200x -250, graphed below, indicates how much profit he makes in a month
viktelen [127]
Here is our profit as a function of # of posters
p(x) =-10x² + 200x - 250
Here is our price per poster, as a function of the # of posters:
pr(x) = 20 - x
Since we want to find the optimum price and # of posters, let's plug our price function into our profit function, to find the optimum x, and then use that to find the optimum price:
p(x) = -10 (20-x)² + 200 (20 - x) - 250
p(x) = -10 (400 -40x + x²) + 4000 - 200x - 250
Take a look at our profit function. It is a normal trinomial square, with a negative sign on the squared term. This means the curve is a downward facing parabola, so our profit maximum will be the top of the curve.
By taking the derivative, we can find where p'(x) = 0 (where the slope of p(x) equals 0), to see where the top of profit function is.
p(x) = -4000 +400x -10x² + 4000 -200x -250
p'(x) = 400 - 20x -200
0 = 200 - 20x
20x = 200
x = 10                         
p'(x) = 0 at x=10. This is the peak of our profit function. To find the price per poster, plug x=10 into our price function:
price = 20 - x
price = 10
Now plug x=10 into our original profit function in order to find our maximum profit:
<span>p(x)= -10x^2 +200x -250
p(x) = -10 (10)</span>² +200 (10) - 250
<span>p(x) = -1000 + 2000 - 250
p(x) = 750

Correct answer is C)
</span>
7 0
3 years ago
What number can replace the n in n/12 to make it equivalent to 1/2 ?<br> 6<br> 8<br> 9<br> 10
Ierofanga [76]

Answer:

i believe the answer is 6.

4 0
3 years ago
Read 2 more answers
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