$(x-h)^2+(y-k)^2=r^2$ where h and k are the circle's center and r is the radius. We are told, and we can see, that the center of the circle is (0, 0) so h = 0 and k = 0. The radius, given as 4, goes into the equation squared, so the equation is

$(x-0)^2+(y-0)^2=16$ which simplifies down to

$x^2+y^2=16$ , choice C.

8 0

3 years ago

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Image Which of the following statements is true for ∠a and ∠b in the diagram?

saveliy_v [14]

Answer:

You have not added a picture soi can not help answer this question.

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3 0

2 years ago

HELP PLSS<br><br> What is the slope of the line that passes through the points (-2, -5) and (6, 7)?

Serjik [45]

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$slope = \frac{7 - ( - 5)}{6 - ( - 2)} \\$

$slope = \frac{7 + 5}{6 + 2} \\$

$slope = \frac{12}{8} \\$

$slope = \frac{4 \times 3}{4 \times 2} \\$

$slope = \frac{3}{2} \\$

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3 0

3 years ago

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