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Oduvanchick [21]
2 years ago
13

I need helppp.....?????

Mathematics
1 answer:
Ksenya-84 [330]2 years ago
4 0

Answer:

G is the answer

Step-by-step explanation:

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In 1991, the moose population in a park was measured to be 1900. By 1997, the population was measured again to be 3600. If the p
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Answer:

Since this is a linear (non-exponential) population problem you can just use the standard y=mx+b form of an equation. Where m = (change in population/change in years)

The numbers you were provided state that over the course of 7 years (1998-1991) the population increased by 420 people (4130-3710). So, (420/7) = 60 = m. Assuming that the growth rate for 1990 is the same as 1991. then you would have a starting population of (3710-60) or 3650, that would be your "b" value since at t=0 P(t) = 3650. This yields a final equation of P(t) = 60t +3650. Check the answer at t=1 and you get the population during 1991: 3710.

Step-by-step explanation:

.

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2 years ago
The coordinates of the vertices of △RST are R(−3,1), S(−1,4), and T(3,1) .
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3 years ago
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3 years ago
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which method for comparing fractions were you unaware of before reading? use it to compare 2/3 and 3/4​
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Answer:

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Step-by-step explanation:

2/3 = (2*4)/(3*4)=8/12

3/4 = (3*3)/(4*3)=9/12

Since 9/12>8/12 then 3/4>2/3

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\text { greatest common factor =  } 4ab
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