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2 years ago

14

Help if you can Please no links or false answers

2 answers:

Svetlanka [38]2 years ago

7 0

Answer:

1st option

Step-by-step explanation:

given a quadratic function in standard form

f(x) = ax² + bx + c ( a ≠ 0 ) , then

• if a > 0 , the function opens up and has a minimum

• if a < 0 , the function opens down and has a maximum

here a = $\frac{1}{2}$ > 0

then f(x) opens up and has a minimum

BARSIC [14]2 years ago

7 0

Answer:

Option A, open up and have a minimum

Step-by-step explanation:

<u>Step 1: Determine if it opens up or down</u>

Since the value of a is 1/2 which means that it's positive which also means that it opens up. When a parabola opens up, that means that it has a minimum.

The picture attached to this answer shows an example of how a graph would look when using this equation. If a was -1/2 then the parabola would be facing down and would have a maximum.

Answer: Option A, open up and have a minimum

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Write an equation in slope-intercept form of the line that passes through (6,-2) and (12,1)

yarga [219]

Equation in slope-intercept form of the line that passes through (6,-2) and (12,1) is:

$y =\frac{1}{2}x-5$

Step-by-step explanation:

Given points are:

(x1,y1) = (6,-2)

(x2,y2) = (12,1)

The slope intercept form is:

$y=mx+b$

We have to find the slope first

$m =\frac{y_2-y_1}{x_2-x_1}\\=\frac{1-(-2)}{12-6}\\= \frac{1+2}{6}\\=\frac{3}{6}\\=\frac{1}{2}$

Putting the value of slope

$y = \frac{1}{2}x+b$

To find the value of b, putting (12,1) in the equation

$1 = \frac{1}{2}(12)+b\\1 = 6+b\\b = 1-6\\b=-5$

Putting the values of m and b

$y =\frac{1}{2}x-5$

Hence,

Equation in slope-intercept form of the line that passes through (6,-2) and (12,1) is:

$y =\frac{1}{2}x-5$

Keywords: Equation of line, slope-intercept form

Learn more about equation of line at:

#LearnwithBrainly

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3 years ago

Will mark the brainiest! What are the coordinates of the vertex of the graph of f(x)=−3|x−1|?

AleksAgata [21]

Answer:

well, the cheap answer is

f(x) = -3| x - 1 | is really just f(x) = -3| x - 1 | + 0.

now, what value of "x" makes the absolute value expression to 0?

well, let's just set it to 0 and check,

x - 1 = 0

x = 1

so if "x" ever becomes 1, the | x - 1| will turn to 0, therefore, the vertex is at

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3 years ago

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Answer:

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Step-by-step explanation:

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3 years ago

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Answer:

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3 years ago

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