twice as many cats (as) dogs.
c = 2d [not true]
Three less than twice as many cats (as) dogs.
c = 2d - 3
210 combined,
c + d = 210
Subtracting,
-d = 2d - 3 - 210
-3d = -213
d = 71
Answer: 71
Answer:
105.23-101.48=3.75
3.75/5=0.75
Step-by-step explanation:
First, let the number of skis rented by x and the number of snowboards rented by y. We can then assemble the first equation from the amount of money made from the rentals.
44x + 58y = 2232
The second equation can come from the fact that 9 more skis were rented than snowboards.
y = x - 9
Therefore our system is:
44x + 58y = 2232
y = x - 9
Answer:
r = √13
Step-by-step explanation:
Starting with x^2+y^2+6x-2y+3, group like terms, first x terms and then y terms: x^2 + 6x + y^2 -2y = 3. Please note that there has to be an " = " sign in this equation, and that I have taken the liberty of replacing " +3" with " = 3 ."
We need to "complete the square" of x^2 + 6x. I'll just jump in and do it: Take half of the coefficient of the x term and square it; add, and then subtract, this square from x^2 + 6x: x^2 + 6x + 3^2 - 3^2. Then do the same for y^2 - 2y: y^2 - 2y + 1^2 - 1^2.
Now re-write the perfect square x^2 + 6x + 9 by (x + 3)^2. Then we have x^2 + 6x + 9 - 9; also y^2 - 1y + 1 - 1. Making these replacements:
(x + 3)^2 - 9 + (y - 1)^2 -1 = 3. Move the constants -9 and -1 to the other side of the equation: (x + 3)^2 + (y - 1)^2 = 3 + 9 + 1 = 13
Then the original equation now looks like (x + 3)^2 + (y - 1)^2 = 13, and this 13 is the square of the radius, r: r^2 = 13, so that the radius is r = √13.
Get y by itself...
y= -(jV-82)/(V-61)