You need to use this formula:
([a]/[sinA])=([c]/[sinC])-I am going to use 'a' for the x, and 'c' for 16(square root of 3)
Now its just getting 'a' by itself.
([c] times [sinA])/([sinC])=[a]
[c]=16 square root of 3
sinA=sin(60)=(square root of 3)/2
sinC=sin(90)=1
Plug it in to get 24 for a, or x. Do the same to figure out y with the new sides.
The final y is:
8 square root of 3
Final answer is C.
Answer: x = 0; x=10
Step-by-step explanation:
Hope this helps!
<em>HOPE</em><em> </em><em>THIS</em><em> </em><em>WILL</em><em> </em><em>HELP</em><em> </em><em>U</em><em>.</em><em>.</em><em>.</em>
Answer:
the answer is x>17 I hope it helps you and next time use mathpapa
Rewrite it in the form a^2 - b^2, where a = 2x and b = 5
(2x)^2 - 5^2
Use the Difference o Squares: a^2 - b^2 = (a + b)(a - b)
<u>(2x + 5)(2x - 5) </u>
