We want to find the median for the given density curve.
The value of the median is 1.
Let's see how to solve this.
First, for a regular set {x₁, ..., xₙ} we define the median as the middle value. The difference between a set and a density curve is that the density curve is continuous, so getting the exact middle value can be harder.
Here, we have a constant density curve that goes from -1 to 3.
Because it is constant, the median will just be equal to the mean, thus the median is the average between the two extreme values.
Remember that the average between two numbers a and b is given by:
(a + b)/2
So we get:
m = (3 + (-1))/2 = 1
So we can conclude that the value of the median is 1, so the correct option is the second one, counting from the top.
If you want to learn more, you can read:
brainly.com/question/15857649
Let m and j be the current ages of Matthew and Jenny, respectively.
Now, Matthew is 3 times as old as Jenny, so the variables are in the following relation:
In 7 years, both of them will be 7 years older, i.e. their ages will be m+7 and j+7, and Matthew will be twice as old:
Now, remembering that m=3j, we can rewrite the second equation as
So, Jenny is 7 and Matthew is 21 (he's 3 times older).
In fact, in 7 years, they will be 14 and 28, and Matthew will be twice as old.
Answer:
9(x + 2) = x - 6
9x+18=x-6
9x-x=-18-6
8x=-24
x=-24/8=-3 is your answer
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Slope-intercept form: y = mx + b
(m is the slope, b is the y-intercept or the y value when x = 0 --> (0, y) or the point where the line crosses through the y-axis)
x = the number of weeks she mows the lawn
y = the amount of money in Jana's savings account
y = 25x + 125
[amount of money in savings account(y) = $125 plus $25 per week(x)]
y-intercept = 125
So if x = 0 weeks and y = $125 in the savings account, $125 was already/initially in the savings account before she started earning and depositing $25 per week. Your answer is C
