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3 years ago

How long does it take for an STD to appear?

1 answer:

4 0

This depends on which sexually transmitted infection (STI) you have. Some STIs cause few or no symptoms, so you may not know you have one.

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What are some dietary factors that affect iron absorption?

Crank

Answer:

Meat fish and poultry

Explanation:

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3 years ago

Why do you think some teenagers don’t feel comfortable talking about their mental health? Explain your answer

Rus_ich [418]

Answer:

bc they just dont

Explanation:

so yeeeee

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3 years ago

An egg is released from the ovary but is not fertilized. Which process occurs about two weeks later?

Liula [17]

A. menstruation

menstruation happens because each month the body releases an egg. Hence why when youre pregnant you dont experience menstruation, because the egg is fertilized so will not be released

7 0

3 years ago

Read 2 more answers

Differentiate the following functions (i) x(1+x)^3

statuscvo [17]

Answer:

$\displaystyle y' = (1 + x)^2(4x + 1)$

General Formulas and Concepts:

Algebra I

Terms/Coefficients
Functions
Function Notation
Factoring

Calculus

Derivatives

Derivative Notation

Derivative Property [Addition/Subtraction]: $\displaystyle \frac{d}{dx}[f(x) + g(x)] = \frac{d}{dx}[f(x)] + \frac{d}{dx}[g(x)]$

Basic Power Rule:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Derivative Rule [Product Rule]: $\displaystyle \frac{d}{dx} [f(x)g(x)]=f'(x)g(x) + g'(x)f(x)$

Derivative Rule [Chain Rule]: $\displaystyle \frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)$

Explanation:

Step 1: Define

Identify

y = x(1 + x)³

Step 2: Differentiate

Product Rule [Derivative Rule - Chain Rule]: $\displaystyle y' = \frac{d}{dx}[x] \cdot (1 + x)^3 + x \cdot \frac{d}{dx}[(1 + x)^3] \cdot \frac{d}{dx}[1 + x]$
Derivative Property [Addition/Subtraction]: $\displaystyle y' = \frac{d}{dx}[x] \cdot (1 + x)^3 + x \cdot \frac{d}{dx}[(1 + x)^3] \cdot (\frac{d}{dx}[1] + \frac{d}{dx}[x])$
Basic Power Rule: $\displaystyle y' = x^{1 - 1} \cdot (1 + x)^3 + x \cdot 3(1 + x)^{3 - 1} \cdot (0 + x^{1 - 1})$
Simplify: $\displaystyle y' = (1 + x)^3 + 3x(1 + x)^2$
Factor: $\displaystyle y' = (1 + x)^2 \bigg[ (1 + x) + 3x \bigg]$
Combine like terms: $\displaystyle y' = (1 + x)^2(4x + 1)$

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Derivatives

Book: College Calculus 10e

5 0

3 years ago

Which of the following muscles is lengthened in Lower Crossed Syndrome? Select one: a. Psoas minor b. Rectus femoris c. Erector

Sav [38]

Answer:

D- TRANSVERSE ABDOMINIS

Explanation:

Transverse abdominis is the innermost layer of the abdominals that is the anterior and lateral abdominal wall which is key to every movement a person make and it helps stabilize the core and spine to help the body function correctly by compressing the abdomen.

TRANSVERSE ABDOMINIS is the muscles that is lengthened in Lower Crossed Syndrome.

3 0

3 years ago