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lesya692 [45]
3 years ago
11

Where does spermatogenesis take place? vas deferens urethra testes penis

Biology
2 answers:
Alenkinab [10]3 years ago
7 0

Answer:

Testes

Explanation:

Spermatogenesis is the process by which haploid mature spermatozoa is produced from diploid germ cells through meiosis and cell differentiation in the male reproductive organ, TESTIS. Spermatogenesis is one of the forms of gametogenesis that occurs in males, as the other (oogenesis) occurs in females.

The testes are composed of numerous thin, tightly coiled tubules known as the SEMINIFEROUS TUBULES, whose wall the production of sperm takes place.

The process of spermatogenesis begins when diploid germ cells called Spermatogonia, undergoes mitotic division to produce two identical daughter cells. One of these cells (A-spermatogonium) will be used to replenish the pool of spermatogonia i.e ensure that the male is fertile throughout his adult life, while the other (B-spermatogonium) will eventually form the mature sperm cell.

This B-spermatogonium replicates by undergoing mitosis to form identical cells known as Primary spermatocyte. The primary spermatocytes undergo meiosis I to produce two haploid cells called secondary spermatocytes. These two cells undergo meiosis II to produce a total of four haploid cells called Spermatids.

N.B: This series of mitotic and meiotic divisions is called Spermatocytogenesis.

The Spermatids are released into the lumen of the seminiferous tubules from the seminiferous epithelium, a process known as Spermiation. In the seminiferous tubules, the spermatids undergo series of metarmophic change and differentiation into mature spermatozoa, until they reach the epididymis. This structural change, where the spermatids undergo nuclear condensation, formation of acrosomal cap and development of a tail, is known as Spermiogenesis.

The spermatozoa becomes stored in the epididymis and undergoes further maturation.

Vitek1552 [10]3 years ago
4 0

Answer:

seminiferous tubules

Explanation:

Spermatogenesis is the process by which the male gametes, called sperm, are created. Spermatogenesis takes place in the seminiferous tubules, which are an intricate system of tubules in the testes where spermatogenesis takes place.

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The bones from an animal found at an archaeological dig have a C614 activity of 0.10 Bq per gram of carbon. The half-life of C61
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C14 is an isotope used in radiocarbon dating techniques to date organic matter remains. The age of these bones is approximately<u> 6890 years.</u>

<h3>What is Carbon 14?</h3>

Carbon 14, also known as radiocarbon, is a radioactive carbon isotope.

Isotopes are the atoms of the same element -carbon- that vary in neutrons and, hence, in their massic number. They are alternative forms of the same element.

The radioactive C14 nucleus contains 6 protons and 8 neutrons and has a half-life of 5730 years.

The term half-life is a reference. It means that an organism that has been dead for 5730 years has half the C14 amount or concentration than the same organism had when it was alive.

Knowing the half-life of an element is useful to determine the age of the dead matter.

C14 is used in radiocarbon dating techniques or methods to estimate the age of fossils. This is a reliable technique used for dating organic samples that are less than 50,000 years old.

<u>Available data</u>:

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  • Bones activity of 0.10 Bq per gram of carbon

To answer this question we can make use of the following equation

Ln (C14T₁/C14 T₀) = - λ T₁

Where,

  • C14 T₀ ⇒ Amount of carbon in a living body. We know, by bibliography, that living organism activity is 0.23 Bq per gram of carbon. So, C14 T₀ = 0.23 Bq/g
  • C14T₁ ⇒ Amount of carbon in the dead body. C14T₁ = 0.1 Bq/g
  • λ ⇒ radioactive decay constant = (Ln2)/T₀,₅
  • T₀,₅ ⇒ The half-life of carbon 14 = 5730 years
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  • T₁ = Age of bones

Let us first calculate the radioactive decay constant.

λ = (Ln2)/T₀,₅

λ = 0.693/5730

<u>λ = 0.0001209</u>

Now, let us calculate the first term in the equation

Ln (C14T₁/C14 T₀) = Ln (0.1/0.23) = Ln 0.4347 =<u> - 0.833</u>

Finally, let us replace the terms, clear the equation, and calculate the value of T₁.

Ln (C14T₁/C14 T₀) = - λ T₁

- 0.833 = - 0.0001209 x T₁

T₁ = - 0.833 / - 0.0001209

T₁ =  6889.99 ≅ <u>6890 years</u>

The bones are approximately<u> 6890 years.</u>

You can learn more about dating organic matter with carbon14 at

brainly.com/question/4149380

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